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Bogoliubov Excitations of Inhomogeneous Bose-Einstein ...

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0.8<br />

0.6<br />

0.4<br />

0.2<br />

3. Disorder<br />

Cd(r/σ)<br />

1<br />

1 2 3 4 5 6<br />

(a)<br />

d = 1<br />

d = 2<br />

d = 3<br />

r<br />

σ<br />

Sd<br />

(2π) d (kσ)d Cd(kσ)<br />

1<br />

0.8<br />

0.6<br />

0.4<br />

0.2<br />

0.5 1 1.5 2<br />

Figure 3.3.: Speckle correlation functions in d = 1, 2, 3. (a) real-space representation.<br />

(b) k-space representation. For the sake <strong>of</strong> comparable scales, Sd(kσ) d Cd(kσ)/(2π) d is<br />

plotted.<br />

whether the speckle potential is repulsive or attractive, see figure 4.8 on<br />

page 97. Because <strong>of</strong> Eq. (3.2), the intensity probability distribution is a<br />

negative exponential with a baseline at zero intensity and arbitrarily high<br />

peaks in the exponential tail. Then, the potential has the skewed probability<br />

distribution with zero mean<br />

(b)<br />

d = 1<br />

d = 2<br />

d = 3<br />

P (w)dw = Θ(w + 1)e −(w+1) dw, with w = V (r)/V0. (3.10)<br />

When computing the two-point correlator <strong>of</strong> the intensity, the convolution<br />

<strong>of</strong> the field correlator γ(k) with itself occurs. The potential correlator<br />

VkV −k ′ = (2π) d δ(k − k ′ )σ d V 2<br />

0 Cd(kσ) (3.11)<br />

defines the dimensionless k-space correlation function Cd(kσ). Being the<br />

convolution <strong>of</strong> two d-dimensional spheres <strong>of</strong> radius σ −1 , Cd(kσ) is centered<br />

at k = 0 and vanishes for k > 2σ −1 , see figure 3.3(b). In one dimension, the<br />

speckle correlation function<br />

C1(kσ) = π(1 − kσ/2) Θ(1 − kσ/2) (3.12a)<br />

has the particularly simple shape <strong>of</strong> a triangle, the convolution <strong>of</strong> a 1D box<br />

with itself. In two and three dimensions, the convolutions <strong>of</strong> disks and balls,<br />

respectively, are slightly more complicated<br />

62<br />

C2(kσ) =<br />

�<br />

8 arccos(kσ/2) − 2kσ � 4 − k2σ2 �<br />

Θ(1 − kσ/2)<br />

kσ<br />

(3.12b)<br />

C3(kσ) = 3π2<br />

8 (kσ − 2)2 (4 + kσ) Θ(1 − kσ/2). (3.12c)

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