Solutions Communications Technology II WS 2011/2012

3 WS 2011/2012 “Communications Technology II” – SolutionsSolution to exercise 3 (eq09):a) Total impulse response:g(i) = f(i)∗e(i) = [1,−α,+α 2 ,−α 3 ,0]+[0,α,−α 2 ,α 3 ,−α 4 ]g(i) = δ(i)−α 4 ·δ(i−4)b)G(z) = 1−α 4 z −4z 0,ν = |α|·e j·π 2·ν , ν = 0...3c) ( SN)d) General equalizer of the order n:e(i) =ISI= 1 α 8Max{∆d(i)} = α 4∑n−1(−1) l α l δ(i−l)l=0f(i)∗e(i) = δ(i)−(−1) n ·α n ·δ(i−n)( S=N)1ISIα 2nMax{∆d(i)} = α n