Solutions Communications Technology II WS 2011/2012

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“Communications Technology II” – Solutions WS 2011/2012 6d(i)d(i−2) y(i)+1+j +1+j +1.25+j ∗0.75+1+j −1+j +1.25+j ∗1.25+1+j −1−j +0.75+j ∗1.25+1+j +1−j +0.75+j ∗0.75−1+j +1+j −0.75+j ∗0.75−1+j −1+j −0.75+j ∗1.25−1+j −1−j −1.25+j ∗1.25−1+j +1−j −1.25+j ∗0.75−1−j +1+j −0.75−j ∗1.25−1−j −1+j −0.75−j ∗0.75−1−j −1−j −1.25−j ∗0.75−1−j +1−j −1.25−j ∗1.25+1−j +1+j +1.25−j ∗1.25+1−j −1+j +1.25−j ∗0.75+1−j −1−j +0.75−j ∗0.75+1−j +1−j +0.75−j ∗1.251.510.5imag0−0.5−1−1.5−1.5 −1 −0.5 0 0.5 1 1.5reald) The squared magnitude frequency response can be calculated by|W(Ω)| 2 = (1−j0.25e j2Ω )(1+j0.25e −j2Ω ) (1)= 1+0.25 2 −j0.25(e j2Ω −e −j2Ω ) (2)= 1.0625+0.5sin(2Ω) (3)
7 WS 2011/2012 “Communications Technology II” – Solutions1.81.61.41.2|W(Ω)| 210.80.60.40.200 pi/4 pi/2 pi 0Ω
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Solutions Communications Technology II WS 2011/2012

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