MARKING SCHEME
MARKING SCHEME
MARKING SCHEME
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2008 Autumn Paper 1 (Non calculator)2 Tier Foundation Tier Marks15. (a) 302 + 2°B1POST CONFERENCE MARK <strong>SCHEME</strong> (13/11/2008)Comments (Page 3)C.A.O. Do not accept 058°.(b) Their 145° bearing from ATheir 243° bearing from BTown C.I1016. (a) For 200, 3000 and 600 (giving 1000)OR 150, 3000 and 600 (giving 750)OR 100, 3000 and 600 (giving 500)EstimateI8165(b) × 100300= 55 (%)M1M1A14M1A1M1A1+ 2° Use overlay. Watch for an unambiguous point on one orboth of the correct bearings and award the mark(s).F.T. if at least M1 and 2 intersecting lines.If the correct point C is unambiguously indicated even withoutthe bearing lines then award M1, M1, A1.For reasonable estimates that lead to a simple calculation.(Cancelling /single digit arithmetic).In the range 500 – 1000 inclusive.C.A.O. SC1 for 55/100I11a17. (a) Idea of ordered pairs plotted.At least 7 plotted correctly, not joined.(b) Positive (correlation).(c) Line of best fit by eye.I1318. (a)Line through (61,59)(d) From their line(b) 33 , 3 , 3 , 7 , 7I1419. (a) PlotsCurve3 3 × 7 24M1A1B1M1A1B16M1A1B1B14P1C1At least 4 points plotted correctly. Within 2mmsquare.C.A.O.Must have positive gradient, look fit for purpose and have atleast 3 points above their line and 3 points below their line.If point not plotted, then the line must pass through the 2mmsquare 60-62/58-60 inclusive.F.T. if their line has a positive gradient. Reading should beexact, if the point is on the grid lines, else it should be read toeither side of the 2mm square, if the point is inside a square.Axes interchange is marked as correct then MR−1For a method that produces 2 prime factors fromthe set {3, 3, 3, 7, 7} before their second error. If their 2 nd primeand 2 nd error occurs at the same ‘level’ then allow M1.C.A.O. for the five correct factors. (Ignore 1s).F.T. their answer if at least one index form used with at least asquare. Ignore prime number requirement for this B mark.Use of brackets (3 3 )(7 2 ) OR dot 3 3 .7 2 gets the B1.The inclusion of any 1s as factors, for example, 3 3 ×7 2 ×1in their index form gets B0.F.T. their (a) if the M1 awarded.Allow B1 for 3969 OR 3 4 × 7 2P0 on 2 nd errorMust be a curve at least for x = −2 to x = 2Within ± ½ asmall square.I1520.(b) Line y = 6x-valuesAngle bisector of ∠ADC,Line parallel to AB distance 3cm from it.L1B14B1B1F.T. their graph if at least 2 readingsUse overlayLoci do not have to be accurate as long as the intention is clear.About 2 cm is required to identify the loci.Initially ignore extra horizontal lines or extra lines throughD. Then if first B2 awarded, extra lines get a penalty of −1.If a region is drawn this may remove the ambiguity and thelines offered will be identified and no penalty invoked.I17Correct regionB13F.T. if their region is similar to the correct one, i.e. uses a linethrough the angle at D and a line parallel to AB.3