MARKING SCHEME

MATHEMATICS - 2 TIER ALTERNATIVE (PILOT)PAPER 2 - HIGHERQ Alternative Autumn 2008. Higher Paper 2 Mark Comment1 1.(a) All points plotted correctlyB2(e) Positive(f) Line of best fit with points above and below(g) Number of visitors from their line of best fit2 Two correct pointsCorrect straight line drawn3 2x + 20 + 2x + 3x + 5x + 40= number12x = 300x = 254 (a) 87/150x100= 58 (%)(b) 80/100 x 35 + 3528 seen or implied(£) 63(c) (i) 70.1583371….(ii) 6.349112…70.16 AND 6.35(d) Distance / time ( 67.5 / 4.5)4 hours 30 minutes correctly expressed as 4.5 or 4 ½15 (km/hour)B1B1B15B2B13M1A1A13M1A1M1B1A1B1B1B1M1B1A1115 Rhombus drawn correctly B336 Overall strategy, Pythag. & area rect. with triangle19.7 – 13.4 (= 6.3)8.2 2 = h 2 + (19.7-13.4) 2height 2 = 27.55height = 5.2(49…)Complete method to find area86.( ….cm 2 )7 States Not trueStating both same probability or showing 1/6x1/6 forboth8 (a) x 2 + 4x - 12(b) 15x 12(c) 7x 4(d) 25x 6 y 2(e) 1/5-2(f) 8x = 35x = 35/8 or equivalent (4.375)9 5/19 x 665 OR 6/19 x 665 OR 8/19 x 665(£)175 OR (£) 210 OR (£)280The other two shares10 (Mass =) 22.3 x 18.4 x 5.21Division by 10002.1(377672 kg)11 Any 3 of the linesy=x+5, y=-x-10, y=2 and x=-1 drawnCorrect region indicatedB1B1M1A1A1M1A17B1B12B2B1B1B2B1B1M1A110M1A1A13M1m1A13B3B14B1 for at least 3 correct plotsIgnore line of best fit, Penalise joined point to point -1Do not accept descriptions.No line of best fit, B0B1 for one correct pointCAOSC1 for a straight line with correct gradient of 5or thecorrect interceptCAOCAO. Accept x=300/12. Answer only gets SC1 onlyOr alternative complete methodOr alternative complete method, e.g 1.8x35Maybe implied by correct answerFT their 80% of 35 if 35 added AND M1 awardedCAO. Rounded or truncated to at least 1 decimal placeCAO. Rounded or truncated to at least 1 decimal placeFT their answers rounded to 2 dp from evidenceFor 67.5 / “their 4 ½ hours “ ( Accept 4.3, 270 as 4 ½ )Or 270/60 usedCAOAllow +2mm. B2 for triangle of 6, 10 6 or B1 for any twolines one of length 6cm and the other of length 10cm. B1 ifidea correct but slightly out of toleranceCorrect Pythag. statement, 19.7-13.4 maybe incorrectlyevaluated but intention to subtract values is clear.CAOFT their height 2 only if M1 awarded.FT their height (not equal to 8.2)CAO.Stating same probability (chance) implies also 1 st B1 not trueIgnore incorrect probabilities if statement is correct orimpliedB1 for either x 2 with -12 OR for 4xB1 for 2 parts of the productIgnore incorrect simplification. x=35/8 gets M1 A1. Accept4.4 or 4.38Or sight of 35Depends on award of M1Award B2 for any 2 lines OR B1 for any 1 line drawn orindicatedCAO9