Chapter 1 Topics in Analytic Geometry

Chapter 1 Topics in Analytic Geometry Chapter 1 Topics in Analytic Geometry

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•MA112 Section 750001: Prepared by Dr.Archara Pacheenburawana 403.3 Dot Product; ProjectionDefinition of the Dot ProductDefinition 3.3 If u = 〈u 1 ,u 2 〉 and v = 〈v 1 ,v 2 〉 are vectors in 2-space, then the dotproduct of u and v is written as u·v and is defined asu·v = u 1 v 1 +u 2 v 2Similarly, if u = 〈u 1 ,u 2 ,u 3 〉 and v = 〈v 1 ,v 2 ,v 3 〉 are vectors in 3-space, then their dotproduct is defined asu·v = u 1 v 1 +u 2 v 2 +u 3 v 3Note that the dot product of two vectors is a scalar. For example,〈4,−3〉·〈3,2〉 = (4)(3)+(−3)(2) = 6〈1,2,−3〉·〈4,−1,2〉 = (1)(4)+(2)(−1)+(−3)(2) = −4Algebraic Properties of the Dot ProductTheorem 3.7 If u, v, and w are vectors in 2-space or 3-space and k is a scalar, then:(a) u·v = v·u(b) u·(v+w) = u·v+u·w(c) k(u·v) = (ku)·v = u·(kv)(d) v·v = ‖v‖ 2(e) 0·v = 0Angle Between VectorsSuppose that u and v are nonzero vectors in 2-space or 3-space that are positioned so theirinitial pointscoincide. Wedefine the angle between u and v tobe theangleθ determinedby the vectors that satisfies the condition 0 ≤ θ ≤ π.uθvuθvuθvuθvTheorem 3.8 If u and v are nonzero vectors in 2-space or 3-space, and if θ is the anglebetween them, thencosθ = u·v(3.5)‖u‖‖v‖

•MA112 Section 750001: Prepared by Dr.Archara Pacheenburawana 41Example 3.13 Find the angle between(a) u = 〈4,−3,−1〉 and v = 〈−2,−3,5〉(b) u = −4i+5j+k and v = 2i+3j−7k(c) u = i−2j+2k and v = −3i+6j−6kSolution .........Example 3.14 Find the angle ABC if A = (1,−2,3), B = (2,4,−6), and C = (5,−3,2).A(1,−2,3)θB(2,4,−6)C(5,−3,2)Solution .........Interpreting the Sign of the Dot ProductIt will often be convenient to express Formula (3.5) asu·v = ‖u‖‖v‖cosθ (3.6)which expresses the dot product of u and v in terms of the lengths of these vectors andthe angle between them. Since u and v are assumed to be nonzero vectors, this version ofthe formula make it clear that the sign of u·v is the same as the sign of cosθ. Thus, wecan tell from the dot product whether the angle between two vectors is acute or obtuse orwhether the vectors are perpendicular.uθvuθvuθvu·v > 0u·v < 0u·v = 0Direction AnglesIn both 2-space and 3-space the angle between a nonzero vector v and the vectors i, j,and k are called the direction angles of v, and the cosines of these angles are called thedirection cosines of v. Formulas for the direction cosines of a vector can be obtainedform Formula (3.5). For example, if v = v 1 i+v 2 j+v 3 k, thencosα = v·i‖v‖‖i‖ = v 1 v·j, cosβ =‖v‖ ‖v‖‖j‖ = v 2 v·k, cosγ =‖v‖ ‖v‖‖k‖ = v 3‖v‖

•MA112 Section 750001: Prepared by Dr.Archara Pacheenburawana 41Example 3.13 F<strong>in</strong>d the angle between(a) u = 〈4,−3,−1〉 and v = 〈−2,−3,5〉(b) u = −4i+5j+k and v = 2i+3j−7k(c) u = i−2j+2k and v = −3i+6j−6kSolution .........Example 3.14 F<strong>in</strong>d the angle ABC if A = (1,−2,3), B = (2,4,−6), and C = (5,−3,2).A(1,−2,3)θB(2,4,−6)C(5,−3,2)Solution .........Interpret<strong>in</strong>g the Sign of the Dot ProductIt will often be convenient to express Formula (3.5) asu·v = ‖u‖‖v‖cosθ (3.6)which expresses the dot product of u and v <strong>in</strong> terms of the lengths of these vectors andthe angle between them. S<strong>in</strong>ce u and v are assumed to be nonzero vectors, this version ofthe formula make it clear that the sign of u·v is the same as the sign of cosθ. Thus, wecan tell from the dot product whether the angle between two vectors is acute or obtuse orwhether the vectors are perpendicular.uθvuθvuθvu·v > 0u·v < 0u·v = 0Direction AnglesIn both 2-space and 3-space the angle between a nonzero vector v and the vectors i, j,and k are called the direction angles of v, and the cos<strong>in</strong>es of these angles are called thedirection cos<strong>in</strong>es of v. Formulas for the direction cos<strong>in</strong>es of a vector can be obta<strong>in</strong>edform Formula (3.5). For example, if v = v 1 i+v 2 j+v 3 k, thencosα = v·i‖v‖‖i‖ = v 1 v·j, cosβ =‖v‖ ‖v‖‖j‖ = v 2 v·k, cosγ =‖v‖ ‖v‖‖k‖ = v 3‖v‖

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