Cournot Oligopoly and the Theory of Supermodular Games
Cournot Oligopoly and the Theory of Supermodular Games
Cournot Oligopoly and the Theory of Supermodular Games
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120 RABAH AMIRHere, <strong>the</strong> upper bound on <strong>the</strong> possible values that Player i can get follows from<strong>the</strong> definition <strong>of</strong> pay<strong>of</strong>fs <strong>and</strong> Assumption A.3. It is also useful to define <strong>the</strong>closure <strong>of</strong> CM i under pointwise convergence:We are now ready forM i : {v: [0,+∞) → [0, +∞) such that 0 ≤ v ≤ u i (C i )1−δ i<strong>and</strong> v is nondecreasing}.PROPOSITION 1. The infinite-horizon game has a Nash equilibrium in stationarystrategies which are elements <strong>of</strong> LC M 1 × LCM 2 .It is convenient to break down <strong>the</strong> pro<strong>of</strong> <strong>of</strong> Proposition 1 into three distinctlemmas, labeled 1.1–1.3. We first define <strong>the</strong> associated best-response optimizationproblem.Suppose that Player II, say, uses a stationary strategy h ∈ LCM 2 . Then PlayerI’s value function for optimally responding to h (in <strong>the</strong> infinite-horizon game),to be denoted V h , is defined byV h (x) = sup E ∑ ∞t=0 δ 1u 1 (c 1 t )subject to x t+1 ∼ q(· |x t −c 1 t −h(x t )), t = 0, 1,...(3.2)with x 0 = x,where <strong>the</strong> expectation is over <strong>the</strong> unique probability measure induced by x, h<strong>and</strong> a stationary strategy by Player I (see Section 1), <strong>and</strong> <strong>the</strong> supremum may betaken over <strong>the</strong> space <strong>of</strong> all stationary policies (see, e.g., Bertsekas <strong>and</strong> Shreve,1978, Stokey et al., 1989).LEMMA 1.1. In <strong>the</strong> optimization problem (3.2), assume that h ∈ LCM 2 .Then V h ∈ CM 1 <strong>and</strong> V h is <strong>the</strong> unique solution to <strong>the</strong> functional equation∫V h (x) = max{u 1 (c) + δ 1 V h (x ′ ) dF(x ′ | x −c−h(x)): c ∈ [0, K 1 (x)]}.(3.3)Pro<strong>of</strong>. Define <strong>the</strong> map T : CM 1 →CM 1 by∫T (v)(x) = sup{u 1 (c) + δ 1 v(x ′ ) dF(x ′ | x −c−h(x)): c ∈ [0, K 1 (x)]}.(3.4)First, we show that T indeed maps CM 1 into itself. To this end, we start by provingthat <strong>the</strong> suprem<strong>and</strong> in (3.4) is continuous in (c, x). Let c n → c <strong>and</strong> x n → x.Then, since h ∈ LCM 2 , x n − c n − h(x n ) → x − c − h(x). By Assumption A.2(see also (2.1)), we have F(· |x n −c n −h(x n )) → F(· |x−c−h(x)), <strong>and</strong>