Problem 13B
Problem 13B
Problem 13B
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Additional Practice <strong>13B</strong>Givens1. f 15 = 26.7 Hzv = 334 m/sn = 15Solutions15v15(334 m/s)L = ⎯⎯ = ⎯⎯4 f 1 5 4(26.7 Hz)L = 46.9 m2. l = 3.47 mv s = 5.00 × 10 2 m/sn = 3v a = 334 m/sL = ⎯ l vsn(3.47 m)(5.00 × 10 2 m/s)(3)⎯ = ⎯⎯⎯2va2(334 m/s)L = 7.79 m3. n = 19L = 86 mv = 334 m/snvf 19 = ⎯⎯ = ⎯ 19 ( 334m/s)⎯2 L 2(86m)f 19 = 37 HzII4. L = 3.50 × 10 2 mf 75 = 35.5 Hzn = 75f 75 = ⎯ 7 5 v⎯2Lv = ⎯ 2L f75⎯ =752(3.50 × 10 2 m)(35.5 Hz)⎯⎯⎯75v = 331 m/s5. L = 4.7 × 10 −3 ml = 3.76 × 10 −3 ml n = ⎯ 4 L ⎯n4L 4(4.7 × 10 −3 m)n = ⎯⎯ = ⎯⎯ = 5l n (3.76 × 10 −3 m)Copyright © by Holt, Rinehart and Winston. All rights reserved.II Ch. 13–2Holt Physics Solution Manual