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NOTES ON REPRESENTATIONS OF FINITE GROUPS Contents 1 ...

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<strong>NOTES</strong> <strong>ON</strong> REPRESENTATI<strong>ON</strong>S <strong>OF</strong> <strong>FINITE</strong> <strong>GROUPS</strong> 3is a basis of V 2 , then there are some elementsu 1 ⊗ w 1 , u 1 ⊗ w 2 , . . . , u 1 ⊗ w q ,u 2 ⊗ w 1 , u 2 ⊗ w 2 , . . . , u 2 ⊗ w q ,.,u p ⊗ w 1 , u p ⊗ w 2 , . . . , u p ⊗ w q ,forming a basis of V 1 ⊗V 2 (called the product basis). If ρ 1 : G → GL (V 1 ) andρ 1 : G → GL (V 2 ) are two representations, then V 1 ⊗ V 2 is a representation,via the ruleρ(g) (u i ⊗ w j ) = ρ 1 (g)u i ⊗ ρ 2 (g)w j .3. InvariantsDefinition 5. If ρ: G → GL (V ) is a representation, a fixed vector of the representationis a vector v ∈ V so that ρ(g)v = v for every g ∈ G. We denote by V G theset of all fixed vectors. For any vector v ∈ V , we denote by p(v) the vectorp(v) = 1|G|∑ρ(g)v,the average of all of the things that G can do to v. We call p the averaging operator,and sometimes write p(v) as v G .Lemma 1. The averaging operator is linear, and G-invariant, and is a projectionto V G , i.e. p ◦ p = p, and p is the identity on V G .Proof. Linearity is clear. Clearly since we averaged over all of the different elementsof G, p is G-invariant. If v is fixed, each ρ(g) drops out, and we get p(v) = v. Clearlythe p(v) is G-invariant, i.e. the image of p is contained in V G so p ◦ p = p. □g∈G4. SubrepresentationsLemma 2. Suppose that ρ: G → GL (V ) is a representation of a finite group G.Take any inner productv, w ∈ V ↦→ 〈v, w〉 ∈ C.From this inner product, define a new operation, which we will write asand is defined byv, w ∈ V ↦→ 〈v, w〉 G ∈ C,〈v, w〉 G = 1|G|∑〈ρ(g)v, ρ(g)w〉 .g∈G(Average over all ways of getting G to act on the pair v, w of vectors). Then thisnew operation is a G-invariant inner product, i.e.〈ρ(g)v, ρ(g)w〉 G = 〈v, w〉 G ,for any g ∈ G and v, w ∈ V .In particular, V has a G-invariant inner product.

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