ISSN: 2250-3005 - ijcer

International Journal Of Computational Engineering Research (ijceronline.com) Vol. 2 Issue. 832Kg S + 32KgO 2 → 64KgSO 21KgS + 1KgO 2 → 2KgSO 2Oxygen required = 0.005 Kg/Kg MSWSulphur dioxide produced = 2 0.005 = 0.01Kg/KgMSWTable 3 Oxygen Required per Kilogram of MSWConstituent Mass fraction Oxygen required (Kg/Kg MSW)Carbon (C) 0.355 0.947Hydrogen (H) 0.051 0.408Sulphur (S) 0.005 0.005Oxygen (O) 0.239 - 0.239Nitrogen (N) 0.024 ___Moisture 0.25 ___Ash 0.190 ___1.121O 2 required per Kilogram of MSW = 1.121KgAir required per Kilogram of MSW =1.1210.233= 4.811KgWhere air is assumed to contain 23.3% O 2 by massI.e. Stiochiometric air/fuel ratio = 4.811:1For air supply which is 80% in excess (this has been derived from industry experience according to (Chattopadhyay,2006) which suggests that 80% of excess air is just enough to optimize the combustion of solid refuse in the mass -burningsystem.Actual A/F ratio, m air = 4.811 +80100 4. 811 Or alternatively, m air can be found using Eq. (3.14)2.2 Flue gas analysisN 2 supplied = 0.767 8.660= 6.642KgO 2 supplied = 0.233 8.660= 2.012KgIn the product,N 2 = 6.642 + 0.024= 6.666Kg and excessO 2 = 2.012-1.121= 0.891KgThe results are tabulated in Table 4= 8.660/1Table 4 Flue Gas Analysis (Volumetric flue gas analysis).Productm i Kg/Kg miMSW 100%mim i Kg/Kmoln i =mimiWetn n %i iDryn n %i iCO 2 1.302 13.958 44 0.030 9.317 10.135H 2 O 0.459 4.921 18 0.026 8.075 ___SO 2 0.01 0.107 64 0.0002 0.062 0.068O 2 0.891 9.552 32 0.028 8.696 9.459N 2 6.666 71.462 28 0.238 73.913 80.405Total 9.328 100 0.322wet 100 1000.296dryIssn 2250-3005(online) November| 2012 Page 11