Solutions to Unit 1 - The Burns Home Page

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2b) Pperfectn perfectnS116or 1 1 1 12 2 2 22c) P n 3 correct n 1 incorrect3 correct orn Sn S41614we can look at it this way1 1 1 1 4 , we multiply by 4 because there are 4 ways of having 3 correct.2 2 2 43a) (7D7D)3b) (AS7D)3c) (2C2C, 2C3C, 2C4C…10C9C, 10C10C)3d) (AS2C, AS4C, AS6C, AD10C)4a) 6x6=364b) The only way to obtain a sum of 2 is 1 white and 1 red4c) 1R2W1W2R
5a) nS ncards ndice406 240There are 240 possible outcomes5b) The elements of the sample space (card number and suit, number on dice)5ci)Let A represent the event of drawing an even cardLet B represent the event of an even number on dieeven and even P AP BnAnB nS nSP P A B20 3 40 6141 25cii) Let A represent the event of drawing an even cardLet B represent the event of an odd number on dieeven and odd P APBnAnB nS nSP P A B20 3 40 6141 2
Page 1 and 2: Solutions to Unit 4.21a) 7 of diamo
Page 3 and 4: 5c) Pred5d) PB75e) P
Page 5 and 6: )P A 1 P AnA1nSn1nred blocksnum
Page 7 and 8: 12 b) P An An Sntotals 7npossible v
Page 9 and 10: 3c Since all probabilities must add
Page 11 and 12: Therefore HA 30 1614C 24 16 8b i) 1
Page 13 and 14: Unit 4.4 Solutions1a) Let A represe
Page 15 and 16: The probability of the event that a
Page 17 and 18: 9b) Let A represent the event that
Page 19 and 20: 9f) Let A represent the event that
Page 21: 19b) Let A represent the event that
Page 25 and 26: 6a) Let A represent the event of dr
Page 27 and 28: 8c) Let A represent the event of be
Page 29: more 5000 6000P P P3 1 8 8121 spe

Solutions to Unit 1 - The Burns Home Page

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