Solutions to Unit 1 - The Burns Home Page
Solutions to Unit 1 - The Burns Home Page
Solutions to Unit 1 - The Burns Home Page
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2b) Pperfectn perfectnS116or 1 1 1 12 2 2 22c) P n 3 correct n 1 incorrect3 correct orn Sn S41614we can look at it this way1 1 1 1 4 , we multiply by 4 because there are 4 ways of having 3 correct.2 2 2 43a) (7D7D)3b) (AS7D)3c) (2C2C, 2C3C, 2C4C…10C9C, 10C10C)3d) (AS2C, AS4C, AS6C, AD10C)4a) 6x6=364b) <strong>The</strong> only way <strong>to</strong> obtain a sum of 2 is 1 white and 1 red4c) 1R2W1W2R