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Fourier Transforms

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function and kgk 0, then gk is a constant multiple of k. Hence gk Qk, forsome constant Q. This means that yk is of the form yk 2A k 2B k − for constants A and B and where the 2 factor has been included for convenience.Inverting this givesyx 12 2 A k B k − e −ikx dk− Ae ix Be −ix ,in agreement with the earlier form.This illustrates clearly why generalised functions are required for the deployment of the<strong>Fourier</strong> theory. The fundamental solutions of the equations cannot be obtained withoutthem.3.4.3 <strong>Fourier</strong> <strong>Transforms</strong> and <strong>Fourier</strong> SeriesThe complex FS for a real or complex-valued function fx, defined on −,, is given in§1.7 to befx ~ ∑n−c n e inx , where c n 12 fxe −inx dx−and generally the coefficients c n will be complex. We assume that the series converges.Suppose we wish to obtain the FT of this FS, how do we proceed? The function fxdescribes a function that is 2-periodic and if we attempt to integrate over the range−, we meet the same problems as encountered previously. However, if we deal withintervals that are multiples of 2, as with the quantity I 2 k above, then the limiting processand the integral are well-defined. Furthermore, the sequence is composed of goodfunctions.Assuming that such issues can be settled, take the FT of fx in the usual way23

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