Isabelle/HOL Exercises Lists Summation, Flattening
Isabelle/HOL Exercises Lists Summation, Flattening
Isabelle/HOL Exercises Lists Summation, Flattening
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"list_exists P (xs @ ys) = (list_exists P xs ∨ list_exists P ys)"lemma "list_exists (list_exists P) xs = list_exists P (flatten xs)"You could have defined list_exists only with the aid of list_all. Do this now, i.e. definea function list_exists2 and show that it is equivalent to list_exists.2
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