Plane Geometry - Bruce E. Shapiro
Plane Geometry - Bruce E. Shapiro Plane Geometry - Bruce E. Shapiro
282 SECTION 48. PARALLEL LINES IN HYPERBOLIC GEOMETRYTheorem 48.16 If l ‖ m are parallel lines that admit a common perpendicular,the for every d 0 > 0 there exists a point P ∈ m such that d(P, l) > d 0 ;and P may be chosen to line on either side of the common perpendicular.Proof. (omitted)Theorem 48.17 (Transitivity of Limiting Parallels) If l is asymptoticallyparallel to m in the direction −→ AB and l is asymptotically parallel ton in the direction −→ AB, then either m = n or m is asymptotically parallelto n.Proof. (omitted)Theorem 48.18 If l ‖ m then either l and m admit a common perpendicularor l and m are asymptotically parallel.We have already shown that the critical function is decreasing. In fact, itis strictly decreasing.Theorem 48.19 The critical function κ(x) is strictly decreasing.Proof. (See Venema.)Theorem 48.20 If l and m are asymptotically parallel lines then for everyɛ > 0 there exists a point T ∈ m such that d(T, l) < ɛ.Proof. (See Venema.)Theorem 48.21 limx→∞ κ(x) = 0Proof. (See Venema.)Theorem 48.22 limx→0 + κ(x) = 90Proof. (See Venema.)Theorem 48.23 The critical funnction κ(x) is onto.Proof. (Exercise.)Theorem 48.24 The critical functionis continuous.Proof. (Exercise.)κ(x) : (0, ∞) ↦→ (0, 90)« CC BY-NC-ND 3.0. Revised: 18 Nov 2012
Section 49Triangles in HyperbolicGeometryTheorem 49.1 For every ɛ > 0 there exists an isosceles triangle △BP Cwith σ(△BP C) < ɛ and δ(△BP C) > 180 − ɛ.Proof. Let ɛ > 0 be given.Since lim x→∞ κ(x) = 0 there exists some y such that ∀a > y, κ(a) < ɛ/4.Choose one such a.Let △P AB be a triangle with right angle at A and both legs of length a.Since −→−→P B intersects AB then µ(∠AP B) < K(a).Since ∠ABP = ∠AP B,andσ△BP C = µ(∠ACP ) + µ(∠ABP )+ 2µ(∠AP B)= 4µ(∠AP B)< 4κ(a)< ɛδ(△BP C) = 180 − σ(△BP C)< 180 − ɛTheorem 49.2 For every ɛ > 0 there is a right triangle △ABC such thatσ(△ABC) > 180 − ɛ and δ(△ABC) < ɛ.283
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282 SECTION 48. PARALLEL LINES IN HYPERBOLIC GEOMETRYTheorem 48.16 If l ‖ m are parallel lines that admit a common perpendicular,the for every d 0 > 0 there exists a point P ∈ m such that d(P, l) > d 0 ;and P may be chosen to line on either side of the common perpendicular.Proof. (omitted)Theorem 48.17 (Transitivity of Limiting Parallels) If l is asymptoticallyparallel to m in the direction −→ AB and l is asymptotically parallel ton in the direction −→ AB, then either m = n or m is asymptotically parallelto n.Proof. (omitted)Theorem 48.18 If l ‖ m then either l and m admit a common perpendicularor l and m are asymptotically parallel.We have already shown that the critical function is decreasing. In fact, itis strictly decreasing.Theorem 48.19 The critical function κ(x) is strictly decreasing.Proof. (See Venema.)Theorem 48.20 If l and m are asymptotically parallel lines then for everyɛ > 0 there exists a point T ∈ m such that d(T, l) < ɛ.Proof. (See Venema.)Theorem 48.21 limx→∞ κ(x) = 0Proof. (See Venema.)Theorem 48.22 limx→0 + κ(x) = 90Proof. (See Venema.)Theorem 48.23 The critical funnction κ(x) is onto.Proof. (Exercise.)Theorem 48.24 The critical functionis continuous.Proof. (Exercise.)κ(x) : (0, ∞) ↦→ (0, 90)« CC BY-NC-ND 3.0. Revised: 18 Nov 2012