Plane Geometry - Bruce E. Shapiro
Plane Geometry - Bruce E. Shapiro Plane Geometry - Bruce E. Shapiro
194 SECTION 38. THE PYTHAGOREAN THEOREMProof. (Exercise.)Theorem 38.4 (Converse of Pythagorean Theorem) If a 2 + b 2 = c 2then ∠C is a right angle.Proof. We are given △ABC with a 2 + b 2 = c 2 .Construct a right angle at point F on rays −→ −−→F G and F H.Define point E ∈ −−→ F H such that F E = a, and define point D ∈ −→ F G suchthat F D = b. Then △DEF is a right triangle. By the PythagoreanTheoremf 2 = d 2 + e 2 = a 2 + b 2 = c 2This means that f = c and hence by SSS, △ABC ∼ = △DEF .∠C = ∠F = 90.HenceFigure 38.3: Converse of the Pythagorean Theorem.Figure 38.4: Definition of sin θ = BC/AB and cos θ = AC/AB.« CC BY-NC-ND 3.0. Revised: 18 Nov 2012
SECTION 38. THE PYTHAGOREAN THEOREM 195Definition 38.5 (Trigonometry) Let △ABC be a right triangle withright angle at vertex C, and let θ = ∠CAB. Then if θ is acute, we definesin θ = BCABand cos θ =ACABIf θ is obtuse, then let θ ′ = 180 − θ and definesin θ = sin θ ′ and cos θ = − cos θ ′Also, definesin 0 = 0 and cos 0 = 1sin 90 = 1 and cos 90 = 0Theorem 38.6 (Pythagorean Identity)Proof. (Exercise.)sin 2 θ + cos 2 θ = 1Theorem 38.7 (Law of Sines) Let △ABC be any triangle with sidesa, b, c opposite vertices A, B, C. ThenProof. (Exercise.)asin ∠A =bsin ∠B =csin ∠CTheorem 38.8 (Law of Cosines) Let △ABC be any triangle with sidesa, b, c opposite vertices A, B, C. ThenProof. (Exercise.)c 2 = a 2 + b 2 − 2ab cos ∠CRevised: 18 Nov 2012 « CC BY-NC-ND 3.0.
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194 SECTION 38. THE PYTHAGOREAN THEOREMProof. (Exercise.)Theorem 38.4 (Converse of Pythagorean Theorem) If a 2 + b 2 = c 2then ∠C is a right angle.Proof. We are given △ABC with a 2 + b 2 = c 2 .Construct a right angle at point F on rays −→ −−→F G and F H.Define point E ∈ −−→ F H such that F E = a, and define point D ∈ −→ F G suchthat F D = b. Then △DEF is a right triangle. By the PythagoreanTheoremf 2 = d 2 + e 2 = a 2 + b 2 = c 2This means that f = c and hence by SSS, △ABC ∼ = △DEF .∠C = ∠F = 90.HenceFigure 38.3: Converse of the Pythagorean Theorem.Figure 38.4: Definition of sin θ = BC/AB and cos θ = AC/AB.« CC BY-NC-ND 3.0. Revised: 18 Nov 2012