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Crop yield response to water - Cra

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ox 6 Examples for determining ET of canopies with partial cover.The relationship shown in Figure 11 may be approximated between 0 and 70 percentground cover (G%) using the equation:(10) K r,t = -0.00012 (G%) 2 + 0.0226 (G%)The two examples below refer <strong>to</strong> citrus and almond trees where the average horizontalprojection of the tree canopy has diameters of 2.8 and 1.2 m, respectively.Diameter(m)Treespacing(m)% GroundcoverK r,tET o(mm/day)K cET c1(mm/day)Examplecitrus2.8 5 x 4 30.8 0.58 5.0 0.70 2.03Examplealmond1.2 7 x 6 2.7 0.06 7.4 1.05 0.471 ET c = ET o K c K r,tfigure 11 Relationship between tree horizontal projection at midday (Percent ground cover) and thereduction coefficient, K r,t , relating the ET of orchards with partial cover <strong>to</strong> that of mature, fullcover plantations formed by isolated trees (for hedgerows, see Apple Section).K r,t1.00.80.60.40.200 10 20 30 40 50 60 70 80Percent ground cover266crop <strong>yield</strong> <strong>response</strong> <strong>to</strong> <strong>water</strong>

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