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Chapter 1 Topics in Analytic Geometry

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MA112 Section 750001: Prepared by Dr.Archara Pacheenburawana 70Derivatives of Dot and Cross ProductsThe follow<strong>in</strong>g rules provide a method for differentiat<strong>in</strong>g dot products <strong>in</strong> 2-space and 3-spaceand cross product <strong>in</strong> 3-space.ddt [r 1(t)·r 2 (t)] = r 1 (t)· dr 2dt + dr 1dt ·r 2(t) (4.11)ddt [r 1(t)×r 2 (t)] = r 1 (t)× dr 2dt + dr 1dt ×r 2(t) (4.12)Theorem 4.4 If r(t) is a differentiable vector-valued function <strong>in</strong> 2-space or 3-space and‖r(t)‖ is constant for all t, thenr(t)·r ′ (t) = 0 (4.13)that is, r(t) and r ′ (t) are orthogonal vectors for all t.Def<strong>in</strong>ite Integrals of Vector-Valued FunctionsIf r(t) is a vector-valued function that is cont<strong>in</strong>uous on the <strong>in</strong>terval a ≤ t ≤ b, then wedef<strong>in</strong>e the def<strong>in</strong>ite <strong>in</strong>tegral of r(t) over this <strong>in</strong>terval as a limit of Riemann sums, that is,In general, we have∫ ba∫ ba(∫ br(t)dt =∫ bar(t)dt =(∫ br(t)dt =aalimmax △t k →0n∑r(t ∗ k)△t k (4.14)k=1) (∫ b)x(t)dt i+ y(t)dt j 2-space (4.15)a) (∫ b) (∫ b)x(t)dt i+ y(t)dt j+ z(t)dt k 3-space (4.16)aaExample 4.12 Let r(t) = t 2 i+e t j−(2cosπt)k. EvaluateSolution .........∫ 10r(t)dt.Rules of IntegrationAs with differentiat<strong>in</strong>g, many of the rules for <strong>in</strong>tegrat<strong>in</strong>g real-values functions have analogsfor vector-values functions.Theorem 4.5 (Rulesof Integration). Letr(t), r 1 (t), and r 2 (t) be vector-valued functions<strong>in</strong> 2-space or 3-space that are cont<strong>in</strong>uous on the <strong>in</strong>terval a ≤ t ≤ b, and let k be a scalar.Then the follow<strong>in</strong>g rules of <strong>in</strong>tegration hold:

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