Chapter 1 Topics in Analytic Geometry
Chapter 1 Topics in Analytic Geometry Chapter 1 Topics in Analytic Geometry
MA112 Section 750001: Prepared by Dr.Archara Pacheenburawana 44In this formula we call (v·e 1 )e 1 and (v·e 2 )e 2 the vector components of v along e 1 ande 2 , respectively; and we call v · e 1 and v · e 2 the scalar components of v along e 1 ande 2 , respectively.If θ denote the angle between v and e 1 , thenv·e 1 = ‖v‖cosθ and v·e 2 = ‖v‖sinθand the decomposition (3.7) can be expressed asExample 3.16 Letv = 〈2,3〉, e 1 =v = (‖v‖cosθ)e 1 +(‖v‖sinθ)e 2 (3.9)〈 1 √2 ,〉 〈1√ , and e 2 = −√ 1 ,2 2〉1√2Find the scalar components of v along e 1 and e 2 and the vector components of v along e 1and e 2 .Solution .........Example 3.17 A rope is attached to a 100-lb block on a ramp that is inclined at an angleof 30 ◦ with the ground.30 ◦How much force does the block exert against the ramp, and how much force must be appliedto the rope in a direction parallel to the ramp to prevent the block from sliding down theramp?Solution .........Orthogonal ProjectionsThevectorcomponentsofv alonge 1 ande 2 in(3.8)arealsocalledtheorthogonal projectionsof v on e 1 and e 2 and are denoted byproj e1v = (v·e 1 )e 1 and proj e2v = (v·e 2 )e 2In general, if e is a unit vector, then we define the orthogonal projection of v on e tobeproj e v = (v·e)e (3.10)
MA112 Section 750001: Prepared by Dr.Archara Pacheenburawana 45The orthogonal projection of v on an arbitrary nonzero vector b can be obtained by normalizingb and then applying Formula (3.10); that is,( )( )b bproj b v = v·‖b‖ ‖b‖which can be rewritten asproj b v = v·b‖b‖ 2 b (3.11)Moreover, if we subtract proj b v from v, then the resulting vectorv−proj b vwill be orthogonal to b; we call this the vector component of v orthogonal to b.v−proj b vvvv−proj b vbproj b vproj b vbAcute angle between v and bObtuse angle between v and bExample 3.18 Find the orthogonal projection of v = i +j+k on b = 2i+2j, and thenfind the vector component of v orthogonal to b.Solution .........WorkRecall that we define the work W done on the object by a constant force of magnitude Facting in the direction of motion over the distance d to beW = Fd = force × distance (3.12)If we let F denote a force vector of magnitude ‖F‖ = F acting in the direction of motion,then we can write (3.12) asW = ‖F‖dMoreover, if we assume that the object moves along a line from point P to point Q, thend = ‖ −→ PQ‖, so that the work can be expressed entirely in vector form asW = ‖F‖‖ −→ PQ‖The vector −→ PQ is called the displacement vector for the object.In the case where a constant force F is not in the direction of motion, but rather makesan angle θ with the displacement vector, then we define the work W done by F to beW = (‖F‖cosθ)‖ −→ PQ‖ = F·−→ PQ (3.13)
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MA112 Section 750001: Prepared by Dr.Archara Pacheenburawana 44In this formula we call (v·e 1 )e 1 and (v·e 2 )e 2 the vector components of v along e 1 ande 2 , respectively; and we call v · e 1 and v · e 2 the scalar components of v along e 1 ande 2 , respectively.If θ denote the angle between v and e 1 , thenv·e 1 = ‖v‖cosθ and v·e 2 = ‖v‖s<strong>in</strong>θand the decomposition (3.7) can be expressed asExample 3.16 Letv = 〈2,3〉, e 1 =v = (‖v‖cosθ)e 1 +(‖v‖s<strong>in</strong>θ)e 2 (3.9)〈 1 √2 ,〉 〈1√ , and e 2 = −√ 1 ,2 2〉1√2F<strong>in</strong>d the scalar components of v along e 1 and e 2 and the vector components of v along e 1and e 2 .Solution .........Example 3.17 A rope is attached to a 100-lb block on a ramp that is <strong>in</strong>cl<strong>in</strong>ed at an angleof 30 ◦ with the ground.30 ◦How much force does the block exert aga<strong>in</strong>st the ramp, and how much force must be appliedto the rope <strong>in</strong> a direction parallel to the ramp to prevent the block from slid<strong>in</strong>g down theramp?Solution .........Orthogonal ProjectionsThevectorcomponentsofv alonge 1 ande 2 <strong>in</strong>(3.8)arealsocalledtheorthogonal projectionsof v on e 1 and e 2 and are denoted byproj e1v = (v·e 1 )e 1 and proj e2v = (v·e 2 )e 2In general, if e is a unit vector, then we def<strong>in</strong>e the orthogonal projection of v on e tobeproj e v = (v·e)e (3.10)