Chapter 1 Topics in Analytic Geometry
Chapter 1 Topics in Analytic Geometry Chapter 1 Topics in Analytic Geometry
•MA112 Section 750001: Prepared by Dr.Archara Pacheenburawana 42Interpreting the Sign of the Dot ProductIt will often be convenient to express Formula (3.5) asu·v = ‖u‖‖v‖cosθ (3.6)which expresses the dot product of u and v in terms of the lengths of these vectors andthe angle between them. Since u and v are assumed to be nonzero vectors, this version ofthe formula make it clear that the sign of u·v is the same as the sign of cosθ. Thus, wecan tell from the dot product whether the angle between two vectors is acute or obtuse orwhether the vectors are perpendicular.uθvuθvuθvu·v > 0u·v < 0u·v = 0Direction AnglesIn both 2-space and 3-space the angle between a nonzero vector v and the vectors i, j,and k are called the direction angles of v, and the cosines of these angles are called thedirection cosines of v. Formulas for the direction cosines of a vector can be obtainedform Formula (3.5). For example, if v = v 1 i+v 2 j+v 3 k, thencosα = v·i‖v‖‖i‖ = v 1 v·j, cosβ =‖v‖ ‖v‖‖j‖ = v 2 v·k, cosγ =‖v‖ ‖v‖‖k‖ = v 3‖v‖yzjvkvβαixγαβjyxiTheorem 3.9 The direction cosines of a nonzero vector v = v 1 i+v 2 j+v 3 k arecosα = v 1‖v‖ , cosβ = v 2‖v‖ , cosγ = v 3‖v‖
MA112 Section 750001: Prepared by Dr.Archara Pacheenburawana 43The direction cosines of a vector v = v 1 i+v 2 j+v 3 k can be computed by normalizingv and reading off the components of v/‖v‖, sincev‖v‖ = v 1‖v‖ i+ v 2‖v‖ j+ v k‖v‖ k = (cosα)i+(cosβ)j+(cosγ)kMoreover, we can show that the direction cosines of a vector satisfy the equationcos 2 α+cos 2 β +cos 2 γ = 1Example 3.15 Find the direction angles of the vector v = 4i−5j+3k.Solution .........Decomposing Vectors into Orthogonal ComponentsOur next objective is to develop a computational procedure for decomposing a vector intosum of orthogonal vectors. For this purpose, suppose that e 1 and e 2 are two orthogonalunit vectors in 2-space, and suppose that we want to express a given vector v as a sumv = w 1 +w 2so that w 1 is a scalar multiple of e 1 and w 2 is a scalar multiple of e 2 .w 2e 2ve 1 w 1That is, we want to find scalars k 1 and k 2 such thatv = k 1 e 1 +k 2 e 2 (3.7)We can find k 1 by taking the dot product of v with e 1 . This yieldsSimilarly,v·e 1 = (k 1 e 1 +k 2 e 2 )·e 1= k 1 (e 1 ·e 1 )+k 2 (e 2 ·e 1 )= k 1 ‖e 1 ‖ 2 +0 = k 1v·e 2 = (k 1 e 1 +k 2 e 2 )·e 2 = k 1 (e 1 ·e 2 )+k 2 (e 2 ·e 2 ) = 0+k 2 ‖e 2 ‖ 2 = k 2Substituting these expressions for k 1 and k 2 in (3.7) yieldsv = (v·e 1 )e 1 +(v·e 2 )e 2 (3.8)
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MA112 Section 750001: Prepared by Dr.Archara Pacheenburawana 43The direction cos<strong>in</strong>es of a vector v = v 1 i+v 2 j+v 3 k can be computed by normaliz<strong>in</strong>gv and read<strong>in</strong>g off the components of v/‖v‖, s<strong>in</strong>cev‖v‖ = v 1‖v‖ i+ v 2‖v‖ j+ v k‖v‖ k = (cosα)i+(cosβ)j+(cosγ)kMoreover, we can show that the direction cos<strong>in</strong>es of a vector satisfy the equationcos 2 α+cos 2 β +cos 2 γ = 1Example 3.15 F<strong>in</strong>d the direction angles of the vector v = 4i−5j+3k.Solution .........Decompos<strong>in</strong>g Vectors <strong>in</strong>to Orthogonal ComponentsOur next objective is to develop a computational procedure for decompos<strong>in</strong>g a vector <strong>in</strong>tosum of orthogonal vectors. For this purpose, suppose that e 1 and e 2 are two orthogonalunit vectors <strong>in</strong> 2-space, and suppose that we want to express a given vector v as a sumv = w 1 +w 2so that w 1 is a scalar multiple of e 1 and w 2 is a scalar multiple of e 2 .w 2e 2ve 1 w 1That is, we want to f<strong>in</strong>d scalars k 1 and k 2 such thatv = k 1 e 1 +k 2 e 2 (3.7)We can f<strong>in</strong>d k 1 by tak<strong>in</strong>g the dot product of v with e 1 . This yieldsSimilarly,v·e 1 = (k 1 e 1 +k 2 e 2 )·e 1= k 1 (e 1 ·e 1 )+k 2 (e 2 ·e 1 )= k 1 ‖e 1 ‖ 2 +0 = k 1v·e 2 = (k 1 e 1 +k 2 e 2 )·e 2 = k 1 (e 1 ·e 2 )+k 2 (e 2 ·e 2 ) = 0+k 2 ‖e 2 ‖ 2 = k 2Substitut<strong>in</strong>g these expressions for k 1 and k 2 <strong>in</strong> (3.7) yieldsv = (v·e 1 )e 1 +(v·e 2 )e 2 (3.8)