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Glencoe Solution Manual

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41c. P(exactly 20 meters from the starting point) C(10, 6) 1 2 6 1 2 4 C(10, 4) 1 2 4 1 2 61 11 210 6 4 1 6 210 1 6 1 6 4 0.4142. P(sum less than 9 ⏐ both cubes are the same)43 6 —63 6 2 3 43. P(letter is contained in house or phone)5 5 3 2 6 2 6 2 67 2 644a. 80, 75, 70, . . .44b. T 80 5n44c. T 125n 4 0,0001 000or 40125 g 5(40)75 g; 75° F45. 3 x 1 6 x(x 1)log 3 x log 6x log 3 log 3 x log 6x log 3 x log 6 log 3x(log 3 log 6) log 3log3x log 3 log 6x 0.3846. h 0, k 3, a 7, b 5, c 26Center: (0, 3)Foci: (26, 3)Vertices: major axis → (7, 3) and (7, 3)minor axis → (0, 2) and (0, 8)47. 2cos 2 i sin 2 2 0 2 i 0 2iu48. WX 6 8, 5 (3) or 2, 8u⏐WX ⏐ (6 ) 8 2 (5 (3)) 2 (2) 2 8 249.71 cm 68 or 217106˚55 cmdd 2 71 2 55 2 2(71)(55) cos 106°d 101.1 cm71 cm74˚106˚55 cmdd 2 71 2 55 2 2(71)(55) cos 74°d 76.9 cm50. 4⏐ 1 12 21 62 724 32 44 721 8 11 18 ⏐ 0Since the remainder is 0, x 4 is a factor of thepolynomial.Area of page for textArea of entire page51. The answer is 7/12.63 1 08 172 Chapter 13 Study Guide and AssessmentPage 881 Understanding the Vocabulary1. independent 2. failure3. 1 4. probability5. permutation 6. permutation withrepetitions7. mutually exclusive 8. sample space9. conditional 10. combinatoricsPages 882–884 Skills and Concepts11. Using the Basic Counting Principle, 3 2 1 or 6.12. Using the Basic Counting Principle, 5 4 3 2 1or 120.13. Using the Basic Counting Principle,6 5 4 3 2 1 or 720.6!14. P(6, 3) (6 1208!15. P(8, 6) (8 3)!6 5 4 3 2 13 2 1 20,1605!16. C(5, 3) (5 3)! 3! 5 4 3 2 12 1 3 2 1 1011!17. C(11, 8) (11 6)!8 7 6 5 4 3 2 12 18)! 8!11 10 9 8 7 6 5 4 3 2 13 2 1 8 7 6 5 4 3 2 1 1656!18. P ( 6,3)(6 3)!P(5,3) 5! (5 3)!6 5 4 3 2 1 2 1 5 4 3 2 1 3 2 1 25!19. C(5, 5) C(3, 2) (5 (9 1 1)(12 1.5 1.5)9 12 1 1 3 1 33!5)! 5! (3 2)! 2! 2 1 2 1453 Chapter 13

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