Problem 1A
Problem 1A
Problem 1A
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Givens<br />
Solutions<br />
7. m = (200)(2 × 10 30 kg) =<br />
4 × 10 32 kg a. m = 4 × 10 32 10 3 g 10 3 mg<br />
kg × × =<br />
1kg 1 g<br />
4 × 10 38 mg<br />
b. m = 4 × 10 32 kg × ⎯ 1 3<br />
0 g 1 Eg<br />
⎯ × ⎯<br />
1 kg<br />
1 0 1 ⎯<br />
8 = 4 × 10 17 Eg<br />
g<br />
8. area = 166 241 700 km 2<br />
depth = 3940 m<br />
V = volume = area × depth<br />
V = (166 241 700 km 2 )(3940 m) × <br />
⎯ 1 2<br />
000<br />
m<br />
⎯<br />
1 km<br />
<br />
V = 6.55 × 10 17 m 3<br />
a. V = 6.55 × 10 17 m 3 × ⎯ 10 6 3<br />
cm<br />
⎯<br />
1 m3<br />
= 6.55 × 10 23 cm 3<br />
b. V = 6.55 × 10 17 m 3 × ⎯ 10 9<br />
mm 3<br />
⎯<br />
1 m3<br />
= 6.55 × 10 26 mm 3<br />
II<br />
Copyright © by Holt, Rinehart and Winston. All rights reserved.<br />
II Ch. 1–2<br />
Holt Physics Solution Manual
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