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How to make a cone for measuring the volume

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<strong>How</strong> <strong>to</strong> <strong>make</strong> a <strong>cone</strong> <strong>for</strong> <strong>measuring</strong> <strong>the</strong> <strong>volume</strong><br />

For teachers<br />

In teaching elementary and high school geometry, we derive <strong>the</strong> <strong>for</strong>mula <strong>for</strong> <strong>the</strong> <strong>volume</strong> of<br />

a <strong>cone</strong> by comparing <strong>the</strong> <strong>volume</strong> of a cylinder with a <strong>volume</strong> of a <strong>cone</strong> by using rice or<br />

water. In this <strong>to</strong>pic, teachers are required <strong>to</strong> <strong>make</strong> a <strong>cone</strong> and a cylinder accurately in order<br />

<strong>to</strong> get an exact result. Several ma<strong>the</strong>matical methods of making a <strong>cone</strong> by using a paper<br />

(Board paper) are introduced in this handout. You can <strong>make</strong> a <strong>cone</strong> based on <strong>the</strong> size of a<br />

cylinder accurately!<br />

► Utilizing special right triangles<br />

We have already known <strong>the</strong> following special right triangles that <strong>the</strong> ratio of three lengths of<br />

sides is represented by whole numbers. (You can confirm it by using Pythagorean <strong>the</strong>orem.)<br />

We are going <strong>to</strong> utilize it <strong>to</strong> <strong>make</strong> a <strong>cone</strong>.<br />

5<br />

4<br />

5 2 =4 2 +3 2<br />

25=16+9<br />

13<br />

12<br />

13 2 =12 2 +5 2<br />

169=144+25<br />

3<br />

5 4<br />

3<br />

× 2<br />

10<br />

6<br />

8<br />

5<br />

13<br />

5<br />

12<br />

(Example) we are going <strong>to</strong> <strong>make</strong> this <strong>cone</strong> from a shell<br />

<br />

13<br />

6<br />

5<br />

(Circumference of a base)<br />

= Diameter×circular constant<br />

12×π=12×3.14 =37.68= (arc length of a sec<strong>to</strong>r)<br />

↑Not necessary <strong>to</strong> compute<br />

(The central angle of <strong>the</strong> sec<strong>to</strong>r)<br />

The arc length of <strong>the</strong> sec<strong>to</strong>r =<br />

x<br />

20× π × = 12×π<br />

360<br />

diameter ×π ×<br />

20 × x = 12 x = 18×<br />

12 = 216°<br />

360<br />

( central)<br />

angle<br />

360


There<strong>for</strong>e,<br />

The procedure of making a <strong>cone</strong> is below.<br />

○1 Compute <strong>the</strong> circumference of <strong>the</strong> base<br />

○2 Compute <strong>the</strong> central angle of <strong>the</strong> sec<strong>to</strong>r<br />

○3 Draw a line which length is 10cm<br />

○4 Measure <strong>the</strong> central angle that is 216° or<br />

144°(360°-216°)<br />

○5 Draw a line which length is 10cm<br />

○6 Create an arc with <strong>the</strong> use of a compass<br />

(If you need a base of a <strong>cone</strong>, draw a circle<br />

whose radius is 10cm. Also if you need an over<br />

lapping edge, you can create it.)<br />

○7 Cut <strong>the</strong> sec<strong>to</strong>r and <strong>make</strong> it<br />

(Try exercise)<br />

►General method<br />

If you'd like students <strong>to</strong> use several different <strong>cone</strong>s in <strong>the</strong> activity, you can also <strong>make</strong> any<br />

sizes of <strong>cone</strong>s. (But you might need <strong>to</strong> use a calcula<strong>to</strong>r.)<br />

Cylinder<br />

x<br />

2πx<br />

x<br />

y<br />

y<br />

Slant height<br />

2 2<br />

x + y y<br />

x<br />

2<br />

x +<br />

a<br />

y<br />

2<br />

2<br />

2x π = 2×<br />

π × x + y ×<br />

360<br />

2 a<br />

Circumference of <strong>the</strong> base = arc length of <strong>the</strong> sec<strong>to</strong>r<br />

x<br />

Cone<br />

The central angle (a) =<br />

x × 360<br />

x<br />

2<br />

+ y<br />

2<br />

○1 Compute <strong>the</strong> slant height of a <strong>cone</strong> by using Pythagorean <strong>the</strong>orem<br />

○2 Compute <strong>the</strong> circumference of a base<br />

○3 Computer <strong>the</strong> central angle of <strong>the</strong> sec<strong>to</strong>r<br />

○4 Draw a line which length is equal <strong>to</strong> <strong>the</strong> slant height<br />

○5 Measure <strong>the</strong> central angle of <strong>the</strong> sec<strong>to</strong>r (○2 )<br />

○6 Draw a line which length is equal <strong>to</strong> slant height<br />

○7 Create an arc with <strong>the</strong> use of a compass


► Example<br />

We are going <strong>to</strong> use a wafer stick container as a cylinder.<br />

○1 Measure <strong>the</strong> sizes of this container (approximately).<br />

<br />

4.7 cm<br />

<br />

16 cm<br />

Based on this cylinder, we are going <strong>to</strong> <strong>make</strong> a <strong>cone</strong> whose base and height are<br />

congruent <strong>to</strong> <strong>the</strong> corresponding parts of <strong>the</strong> cylinder respectively.<br />

○2 Compute <strong>the</strong> size of <strong>the</strong> shell of a <strong>cone</strong>.<br />

4.7 cm<br />

16 cm<br />

<br />

2<br />

2<br />

16 + ( 4.7) = 256 + 22. 09<br />

= 278.09<br />

= 16.7(<br />

appoximately)<br />

cm<br />

4.7 cm<br />

<br />

a<br />

2× 4.7 × π = 2×<br />

16.7 ×<br />

360<br />

4.7 cm<br />

16.7 cm<br />

9 .4×<br />

360<br />

a =<br />

33.4<br />

=101° (approximately)<br />

○3 Form a <strong>cone</strong> by using scotch tape<br />

Ateneo De Davao University - Regional Science Teaching Center

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