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<strong>16</strong>.6 Weak Acids 627<br />

Solve: (a) NaOH dissociates in water to give one OH ion per formula unit. Therefore,<br />

the OH~ concentration for the solution in (a) equals the stated concentration of NaOH,<br />

namely 0.028 M.<br />

Method 1:<br />

_ 1-0 X IP"14<br />

[H ] ~ 0.028<br />

Method 2:<br />

= 3.57 x 10~53 M pH - -log{3.57 x lO"13) = 12.45<br />

pOH = -log(0.028) = 1.55 pH - 14.00 - pOH = 12.45<br />

(b) Ca(OH)2 is a strong base that dissociates in water to give two OH~ ions per<br />

formula unit. Thus, the concentration of OH~(aq) for the solution in part (b) is<br />

2 X (0.0011 M) - 0.0022 M.<br />

Method 1:<br />

1 n v<br />

[H+]-<br />

0.0022<br />

= 4.55 X ID"12 M<br />

Method 2:<br />

pOH = -log(0.0022) - 2.66<br />

pH = -log(4.55 x 10~12) = 11.34<br />

pH = 14.00 - pOH = 11.34<br />

PRACTICE EXERCISE<br />

What is the concentration of a solution of (a) KOH for which the pH is 11 .f<br />

(b) Ca(OH)2 for which the pH is 11.68?<br />

Answers: (a) 7.8 X 10~3 M; (b) 2.4 X 10"3 M<br />

Although all the hydroxides of the alkali metals (group 1A) are strong electrolytes,<br />

LiOH, RbOH, and CsOH are not commonly encountered in the laboratory.<br />

The hydroxides of the heavier alkaline earth metals, Ca(OH)2, Sr(OH)2,<br />

and Ba(OH)2 , are also strong electrolytes. They have limited solubilities, however,<br />

so they are used only when high solubility is not critical.<br />

Strongly basic solutions are also created by certain substances that react with<br />

water to form OH~(aq). The most common of these contain the oxide ion. Ionic<br />

metal oxides, especially Na2O and CaO, are often used in industry when a strong<br />

base is needed. Each mole of O2~ reacts with water to form 2 mol of OH~, leaving<br />

virtually no O2~ remaining in the solution:<br />

O2-(aq) + H2O(0 - > 2OH~(aq) J [<strong>16</strong>.22]<br />

Thus, a solution formed by dissolving 0.010 rnol of Na2O(s) inienough water to<br />

form 1.0 L of solution will have [OH~] = 0.020 M and a pH of 12.30.<br />

Ionic hydrides and nitrides also react with H2O to form OH~:<br />

H2O(0 - > H2(g) + OrT^) [<strong>16</strong>.23]<br />

3H2O(/) - > NH3(oj) + 3OH~(aq) [<strong>16</strong>.24]<br />

Because the anions O2~, H~, and N3~ are stronger bases than OH~ (the conjugate<br />

base of H2O), they are able to remove a proton from H2O.<br />

<strong>16</strong>.6 Weak Acids _<br />

Most acidic substances are weak acids and are therefore only partially ionized in<br />

aqueous solution. We can use the equilibrium constant for the ionization reaction<br />

to express the extent to which a weak acid ionizes. If we represent a general weak<br />

acid as HA, we can write the equation for its ionization reaction in either of the<br />

following ways, depending on whether the hydrated proton is represented as<br />

or<br />

or<br />

H2O(/)<br />

HA(aiy)<br />

[<strong>16</strong>.25]<br />

[<strong>16</strong>.26]<br />

Students often confuse a weak add<br />

(small Ka) with a dilute add (low<br />

concentration).<br />

|ohn J. Fortman, "Pictorial Analogies<br />

XI: Concentrations and Acidity of<br />

Solutions," /. Chem. Educ., Vol. 71,<br />

1994,430^32-<br />

Todd P. Silverstein, "Weak vs Strong<br />

Acids and Bases: The Football<br />

Analogy," \ Chem. Educ, Vol. 77,<br />

2000, 849-850.

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