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WIND ENERGY SYSTEMS - Cd3wd

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Chapter 5—Electrical Network 5–9<br />

The impedance is<br />

Z = R + jX L − jX C =4+j8 − j11 = 4 − j3 =5/ − 36.87 o<br />

Ω<br />

Assuming V = |V |/0 o is the reference voltage, the current is<br />

The complex power is<br />

I = V Z = 100/0o<br />

5/ − 36.87 o =20/36.87o A<br />

S = |V ||I|̸ θ = (100)(20)/ − 36.87 o = 2000/ − 36.87 o<br />

VA<br />

The real power supplied to the circuit is just the real power absorbed by the resistor, since reactances<br />

do not absorb real power.<br />

It is also given by<br />

P = I 2 R = (20) 2 (4) = 1600 W<br />

The reactive power supplied to the inductor is<br />

P = |V ||I| cos θ = 100(20) cos /36.87 o = 1600 W<br />

The reactive power supplied to the capacitor is<br />

Q L = I 2 X L = (20) 2 (8) = 3200 var<br />

The net reactive power supplied to the circuit is<br />

Q C = −I 2 X C = −(20) 2 (11) = −4400 var<br />

It is also given by<br />

Q = Q L + Q C = 3200 − 4400 = −1200 var<br />

The power factor is<br />

Q = |V ||I| sin θ = 100(20) sin(−36.87 o )=−1200 var<br />

pf = cos θ =cos(−36.87 o )=0.8 lead<br />

The word “lead” indicates that θ is negative, or that the current is leading the voltage.<br />

We see that the real and reactive powers can be found either from the input voltage and<br />

current or from the summation of the component real and reactive powers within the circuit.<br />

Wind Energy Systems by Dr. Gary L. Johnson November 21, 2001

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