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WIND ENERGY SYSTEMS - Cd3wd

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Chapter 3—Wind Measurements 3–23<br />

These roots are<br />

s 2 +2ξω n s + ω 2 n = 0 (27)<br />

s 1 = −ω n ξ + ω n<br />

√ξ 2 − 1<br />

s 2 = −ω n ξ − ω n<br />

√ξ 2 − 1 (28)<br />

We see that the character of the solution changes as ξ passes through unity. For ξ greater<br />

than unity, the roots are real and distinct, but when ξ is less than unity, the roots are complex<br />

conjugates. We shall first consider the solution for real and distinct roots.<br />

Suppose that the vane is at rest with both θ and γ equal to zero, when the wind direction<br />

changes suddenly to some angle γ 1 . We want to find an expression for θ which describes the<br />

motion of the vane. Our initial conditions just after the initial change in wind direction are<br />

θ(0+) = 0 and ω(0+) = 0, because of the inertia of the vane. Since ω = dθ/dt, weseethat<br />

dθ/dt is zero just after the wind direction change. After a sufficiently long period of time<br />

the vane will again be aligned with the wind, or θ(∞) =γ 1 . The latter value would be the<br />

particular solution for this case and would have to be added to Eq. 26 to get the general<br />

solution for the inhomogeneous differential equation, Eq. 23.<br />

θ = A 1 e s1t + A 2 e s2t + γ 1 (29)<br />

Substituting the initial conditions for θ and dθ/dt in this equation yields<br />

0 = A 1 + A 2 + γ 1<br />

0 = A 1 s 1 + A 2 s 2 (30)<br />

Solving these two equations for the coefficients A 1 and A 2 yields<br />

A 1 =<br />

γ 1<br />

s 1 /s 2 − 1<br />

A 2 =<br />

γ 1<br />

s 2 /s 1 − 1<br />

(31)<br />

Wind Energy Systems by Dr. Gary L. Johnson November 12, 2001

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