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A Performance Analysis System for the Sport of Bowling

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3.4.1 Finding <strong>the</strong> Linear Velocity <strong>of</strong> <strong>the</strong> Ball<br />

The following values have already ei<strong>the</strong>r been measured or calculated:<br />

1) The total distance D T <strong>the</strong> ball traveled from release to pin impact (nominally 60<br />

feet from foul line to head pin).<br />

2) The time T it took <strong>for</strong> <strong>the</strong> ball to travel D T feet.<br />

3) The average linear velocity <strong>of</strong> <strong>the</strong> ball v ave = D T / T.<br />

4) The number <strong>of</strong> revolutions R T that occurred in time T.<br />

5) The period t i and angular velocity ω i = 1 / t i <strong>of</strong> each revolution i in R T .<br />

Using <strong>the</strong>se values, an equation can be developed that gives <strong>the</strong> linear velocity v i <strong>for</strong> each<br />

revolution i <strong>of</strong> <strong>the</strong> ball.<br />

Recalling <strong>the</strong> previous calculations <strong>for</strong> R R and R P (<strong>the</strong> fractional revolutions at release and<br />

pin impact), D T can be represented as<br />

D T = R R · (v 1 t 1 ) + v 1 t 1 + v 2 t 2 +....+ v n t n + R P · (v n t n )<br />

= (1+ R R ) · v 1 t 1 + v 1 t 1 + v 2 t 2 +....+ v n t n + (1 + R P ) · v n t n .<br />

By letting t 1 ' = (1 + R R ) · t 1 , t n ' = (1 + R P ) · t n , and t i ' = t i <strong>for</strong> 1 < i < n, <strong>the</strong> above equation<br />

can be reduced to <strong>the</strong> summation<br />

R T<br />

D T = Σ (v i t i ').<br />

i=1<br />

Recall <strong>the</strong> assumption that <strong>the</strong> kinetic energy K <strong>of</strong> <strong>the</strong> ball remains constant from release<br />

to pin impact, and let K i be <strong>the</strong> kinetic energy <strong>of</strong> <strong>the</strong> ball during revolution i. Then<br />

K i = m / 2 (v i + kω 2 i ), where ω i = 1/t i '<br />

and<br />

K 1 = K i = K n , <strong>for</strong> 1 ≤ i ≤ n.<br />

From <strong>the</strong> above,<br />

m / 2 (v 2 1 + kω 2 1 ) = m / 2 (v 2 i + kω 2 i ),<br />

and solving <strong>for</strong> v i in terms <strong>of</strong> v 1 ,<br />

v i = (v 2 1 + k(ω 2 1 - ω 2 i )) ½ .<br />

For constant energy, no energy is lost to friction, and <strong>the</strong> above equation reveals that<br />

friction acts solely to transfer energy from linear momentum to angular momentum. An<br />

expression can now be obtained <strong>for</strong> each velocity v i in terms <strong>of</strong> v 1 . Substituting that<br />

expression into <strong>the</strong> previous summation yields<br />

R T<br />

D T = Σ (v 2 1 + k(ω 2 1 - ω 2 i )) ½ · t i '.<br />

i=1<br />

The value <strong>of</strong> D T is nominally 60 feet, and this summation can be used in developing a<br />

converging iterative solution <strong>for</strong> v 1 . The remaining values <strong>for</strong> v i can be generated from<br />

<strong>the</strong> value found <strong>for</strong> v 1 .<br />

52

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