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GLS (Generalized Least Squares) - Paul Johnson Homepage

GLS (Generalized Least Squares) - Paul Johnson Homepage

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In matrix form, the representation of WLS/<strong>GLS</strong> is<br />

S(ˆb) = (y − ŷ) ′ W (y − ŷ) (12)<br />

and, if you write that out, the sum of squares in a <strong>GLS</strong> framework is a rather more complicated<br />

thing. All of those off-diagonal w ij ’s make the number of terms multiply.<br />

⎡<br />

⎤ ⎡<br />

⎤<br />

w 11 w 12 · · · w 1N y 1 − ŷ 1<br />

[ ]<br />

w 12 w 22 w 2N<br />

y 2 − ŷ 2<br />

y1 − ŷ 1 y 2 − ŷ 2 · · · y N − ŷ N ⎢<br />

⎣ .<br />

.. .<br />

⎥ ⎢<br />

⎥<br />

. ⎦ ⎣ . ⎦<br />

w N1 w N2 · · · w NN y N − ŷ N<br />

= [ ]<br />

y 1 − ŷ 1 y 2 − ŷ 2 · · · y N − ŷ N ⎢<br />

⎣<br />

⎡<br />

w 11 (y 1 − ŷ 1 ) +w 12 (y 2 − ŷ 2 ) · · · +w 1N (y N − ŷ N )<br />

w 12 (y 1 − ŷ 1 ) +w 22 (y 2 − ŷ 2 ) +w 2N (y N − ŷ N )<br />

.<br />

.<br />

.. .<br />

w N1 (y 1 − ŷ 1 ) +w N2 (y 2 − ŷ 2 ) · · · +w NN (y N − ŷ N )<br />

⎤<br />

⎥<br />

⎦<br />

⎡<br />

=<br />

⎢<br />

⎣<br />

w 11 (y 1 − ŷ 1 ) 2 ⎤<br />

+w 12 (y 2 − ŷ 2 )(y 1 − ŷ 1 ) · · · +w 1N (y N − ŷ N )(y 1 − ŷ 1 )<br />

w 12 (y 1 − ŷ 1 )(y 2 − ŷ 2 ) +w 22 (y 2 − ŷ 2 ) 2 +w 2N (y N − ŷ N )(y 2 − ŷ 2 )<br />

.<br />

.. .<br />

⎥<br />

.<br />

⎦<br />

w N1 (y 1 − ŷ 1 )(y N − ŷ N ) +w N2 (y 2 − ŷ 2 )(y N − ŷ N ) · · · +w NN (y N − ŷ N ) 2<br />

w 11 (y 1 − ŷ 1 ) 2 + w 12 (y 2 − ŷ 2 )(y 1 − ŷ 1 ) + · · · + w 1N (y N − ŷ N )(y 1 − ŷ 1 )<br />

= +w 12 (y 1 − ŷ 1 )(y 2 − ŷ 2 ) + w 22 (y 2 − ŷ 2 ) 2 + · · · + w 2N (y N − ŷ N )(y 2 − ŷ 2 )<br />

+w N1 (y 1 − ŷ 1 )(y N − ŷ N ) + w N2 (y 2 − ŷ 2 )(y N − ŷ N ) + · · · + w NN (y N − ŷ N ) 2<br />

Supposing a linear model:<br />

N∑ N∑<br />

= w ij (y i − ŷ i )(y j − ŷ j ) (13)<br />

i=1 j=1<br />

ŷ = Xˆb (14)<br />

The normal equations (the name for the first order conditions) are found by setting the derivatives<br />

of the Sum of <strong>Squares</strong> with respect to the parameters equal to 0.<br />

for each parameter ˆb j :<br />

∂<br />

∂ˆb j<br />

[(y − ŷ) ′ W (y − ŷ)] = 0<br />

If you insert ŷ = Xb in there and do the math (or look it up in a book :) )<br />

(X ′ W X)ˆb − X ′ W y = 0<br />

The WLS/<strong>GLS</strong> estimator is the solution:<br />

ˆb = (X ′ W X) −1 X ′ W y (15)<br />

3

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