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Solução_Calculo_Stewart_6e

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F.<br />

SECTIONTX.10<br />

17.6 PARAMETRIC SURFACES AND THEIR AREAS ET SECTION 16.6 ¤ 287<br />

7. r(u, v) = u 2 +1,v 3 +1,u+ v , −1 ≤ u ≤ 1, −1 ≤ v ≤ 1.<br />

The surface has parametric equations x = u 2 +1, y = v 3 +1, z = u + v,<br />

−1 ≤ u ≤ 1, −1 ≤ v ≤ 1. In Maple, the surface can be graphed by entering<br />

plot3d([uˆ2+1,vˆ3+1,u+v],u=-1..1,v=-1..1);. In<br />

Mathematica we use the ParametricPlot3D command. If we keep u<br />

constant at u 0, x = u 2 0 +1, a constant, so the corresponding grid curves must<br />

be the curves parallel to the yz-plane. If v is constant, we have y = v0 3 +1,<br />

a constant, so these grid curves are the curves parallel to the xz-plane.<br />

9. r(u, v) = u cos v, u sin v, u 5 .<br />

The surface has parametric equations x = u cos v, y = u sin v,<br />

z = u 5 , −1 ≤ u ≤ 1, 0 ≤ v ≤ 2π. Note that if u = u 0 is constant<br />

then z = u 5 0 is constant and x = u 0 cos v, y = u 0 sin v describe a<br />

circle in x, y of radius |u 0 |, so the corresponding grid curves are<br />

circles parallel to the xy-plane. If v = v 0 , a constant, the parametric<br />

equations become x = u cos v 0, y = u sin v 0, z = u 5 .Then<br />

y =(tanv 0 )x, so these are the grid curves we see that lie in vertical<br />

planes y = kx through the z-axis.<br />

11. x =sinv, y =cosu sin 4v, z =sin2u sin 4v, 0 ≤ u ≤ 2π, − π ≤ v ≤ π .<br />

2 2<br />

Note that if v = v 0 is constant, then x =sinv 0 is constant, so the<br />

corresponding grid curves must be parallel to the yz-plane. These<br />

are the vertically oriented grid curves we see, each shaped like a<br />

“figure-eight.” When u = u 0 is held constant, the parametric<br />

equations become x =sinv, y =cosu 0 sin 4v,<br />

z =sin2u 0 sin 4v. Sincez is a constant multiple of y,the<br />

corresponding grid curves are the curves contained in planes<br />

z = ky that pass through the x-axis.<br />

13. r(u, v) =u cos v i + u sin v j + v k. The parametric equations for the surface are x = u cos v, y = u sin v, z = v. We look at<br />

the grid curves first; if we fix v,thenx and y parametrizeastraightlineintheplanez = v which intersects the z-axis. If u is<br />

held constant, the projection onto the xy-plane is circular; with z = v, each grid curve is a helix. The surface is a spiraling<br />

ramp, graph I.<br />

15. r(u, v) =sinv i +cosu sin 2v j +sinu sin 2v k. Parametric equations for the surface are x =sinv, y =cosu sin 2v,<br />

z =sinu sin 2v. Ifv = v 0 is fixed, then x =sinv 0 is constant, and y =(sin2v 0 )cosu and z =(sin2v 0 )sinu describe a<br />

circle of radius |sin 2v 0 |, so each corresponding grid curve is a circle contained in the vertical plane x =sinv 0 parallel to the

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