30.04.2015 Views

Solução_Calculo_Stewart_6e

Solução_Calculo_Stewart_6e

Solução_Calculo_Stewart_6e

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

F.<br />

72 ¤ CHAPTER 2 LIMITS AND DERIVATIVES<br />

TX.10<br />

Hints for Exercises 4 –11: First plot x-intercepts on the graph of f 0 for any horizontal tangents on the graph of f . Look for any corners on the graph<br />

of f— there will be a discontinuity on the graph of f 0 . On any interval where f has a tangent with positive (or negative) slope, the graph of f 0 will be<br />

positive (or negative). If the graph of the function is linear, the graph of f 0 will be a horizontal line.<br />

5. 7.<br />

9. 11.<br />

13. It appears that there are horizontal tangents on the graph of M for t = 1963<br />

and t = 1971. Thus, there are zeros for those values of t on the graph of<br />

M 0 . The derivative is negative for the years 1963 to 1971.<br />

15.<br />

The slope at 0 appears to be 1 and the slope at 1<br />

appears to be 2.7. Asx decreases, the slope gets<br />

closer to 0. Since the graphs are so similar, we might<br />

guess that f 0 (x) =e x .

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!