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Solução_Calculo_Stewart_6e

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F.<br />

TX.10<br />

SECTION 1.2 MATHEMATICAL MODELS: A CATALOG OF ESSENTIAL FUNCTIONS ¤ 13<br />

61. f is an odd function because its graph is symmetric about the origin. g is an even function because its graph is symmetric with<br />

respect to the y-axis.<br />

63. (a) Because an even function is symmetric with respect to the y-axis, and the point (5, 3) is on the graph of this even function,<br />

the point (−5, 3) must also be on its graph.<br />

(b) Because an odd function is symmetric with respect to the origin, and the point (5, 3) is on the graph of this odd function,<br />

the point (−5, −3) must also be on its graph.<br />

65. f(x) = x<br />

x 2 +1 .<br />

f(−x) =<br />

−x<br />

(−x) 2 +1 =<br />

So f is an odd function.<br />

−x<br />

x 2 +1 = − x<br />

x 2 +1 = −f(x).<br />

67. f(x) = x<br />

x +1 ,sof(−x) =<br />

−x<br />

−x +1 =<br />

x<br />

x − 1 .<br />

Sincethisisneitherf(x) nor −f(x), the function f is<br />

neither even nor odd.<br />

69. f(x) =1+3x 2 − x 4 .<br />

f(−x) =1+3(−x) 2 − (−x) 4 =1+3x 2 − x 4 = f(x).<br />

So f is an even function.<br />

1.2 Mathematical Models: A Catalog of Essential Functions<br />

1. (a) f(x) = 5√ x is a root function with n =5.<br />

(b) g(x) = √ 1 − x 2 is an algebraic function because it is a root of a polynomial.<br />

(c) h(x) =x 9 + x 4 is a polynomial of degree 9.<br />

(d) r(x) = x2 +1<br />

is a rational function because it is a ratio of polynomials.<br />

x 3 + x<br />

(e) s(x) =tan2x is a trigonometric function.<br />

(f ) t(x) =log 10 x is a logarithmic function.<br />

3. We notice from the figure that g and h are even functions (symmetric with respect to the y-axis) and that f is an odd function<br />

(symmetric with respect to the origin). So (b) y = x 5 must be f. Sinceg is flatter than h near the origin, we must have<br />

(c) y = x 8 matched with g and (a) y = x 2 matched with h.

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