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Solução_Calculo_Stewart_6e

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F.<br />

(b) 1, − 3π 4<br />

<br />

TX.10<br />

SECTION 10.3 POLAR COORDINATES ¤ 423<br />

r>0: 1, − 3π +2π 4<br />

= <br />

1, 5π 4<br />

r0: −(−1), π + π 2<br />

= <br />

1, 3π 2<br />

r

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