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Solução_Calculo_Stewart_6e

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F.<br />

TX.10<br />

SECTION 9.2 DIRECTION FIELDS AND EULER’S METHOD ¤ 383<br />

7. (a) y(0) = 1<br />

(b) y(0) = 2<br />

(c) y(0) = −1<br />

9.<br />

x y y 0 =1+y<br />

0 0 1<br />

0 1 2<br />

0 2 3<br />

0 −3 −2<br />

0 −2 −1<br />

Note that for y = −1, y 0 =0. The three solution curves sketched go<br />

through (0, 0), (0, −1),and(0, −2).<br />

11.<br />

x y y 0 = y − 2x<br />

−2 −2 2<br />

−2 2 6<br />

2 2 −2<br />

2 −2 −6<br />

Note that y 0 =0for any point on the line y =2x. The slopes are<br />

positive to the left of the line and negative to the right of the line. The<br />

solution curve in the graph passes through (1, 0).<br />

13.<br />

x y y 0 = y + xy<br />

0 ±2 ±2<br />

1 ±2 ±4<br />

−3 ±2 ∓4<br />

Note that y 0 = y(x +1)=0for any point on y =0or on x = −1.<br />

The slopes are positive when the factors y and x +1have the same<br />

sign and negative when they have opposite signs. The solution curve<br />

in the graph passes through (0, 1).

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