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Solução_Calculo_Stewart_6e

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F.<br />

304 ¤ CHAPTER 7 TECHNIQUES OF INTEGRATION<br />

TX.10<br />

7.3 Trigonometric Substitution<br />

1. Let x =3secθ,where0 ≤ θ< π 2 or π ≤ θ< 3π 2 .Then<br />

dx =3secθ tan θdθand<br />

√<br />

x2 − 9= √ 9sec 2 θ − 9= 9(sec 2 θ − 1) = √ 9tan 2 θ<br />

=3|tan θ| =3tanθ for the relevant values of θ.<br />

<br />

<br />

1<br />

x √ 2 x 2 − 9 dx =<br />

<br />

1<br />

9sec 2 θ · 3tanθ 3secθ tan θdθ= 1 9<br />

cos θdθ= 1 sin θ + C = 1 √<br />

x2 − 9<br />

+ C<br />

9<br />

9 x<br />

Note that − sec(θ + π) =secθ,sothefigure is sufficient for the case π ≤ θ< 3π 2 .<br />

3. Let x =3tanθ,where− π 2

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