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Solução_Calculo_Stewart_6e

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F.<br />

TX.10<br />

36 ¤ CHAPTER 1 FUNCTIONS AND MODELS<br />

3. f(x) =x 2 − 2x +3,sof(a + h) =(a + h) 2 − 2(a + h)+3=a 2 +2ah + h 2 − 2a − 2h +3,and<br />

f(a + h) − f(a)<br />

h<br />

= (a2 +2ah + h 2 − 2a − 2h +3)− (a 2 − 2a +3)<br />

h<br />

=<br />

h(2a + h − 2)<br />

h<br />

=2a + h − 2.<br />

5. f(x) =2/(3x − 1). Domain: 3x − 1 6= 0 ⇒ 3x 6= 1 ⇒ x 6= 1 . D = <br />

−∞, 1 3 3 ∪ 1 , ∞ 3<br />

Range: all reals except 0 (y =0is the horizontal asymptote for f.) R =(−∞, 0) ∪ (0, ∞)<br />

7. h(x) =ln(x +6). Domain: x +6> 0 ⇒ x>−6. D =(−6, ∞)<br />

Range: x +6> 0,soln(x +6)takes on all real numbers and, hence, the range is R.<br />

R =(−∞, ∞)<br />

9. (a)Toobtainthegraphofy = f(x)+8,weshiftthegraphofy = f(x) up 8 units.<br />

(b)Toobtainthegraphofy = f(x +8),weshiftthegraphofy = f(x) left 8 units.<br />

(c) To obtain the graph of y =1+2f(x), we stretch the graph of y = f(x) vertically by a factor of 2, and then shift the<br />

resulting graph 1 unit upward.<br />

(d)Toobtainthegraphofy = f(x − 2) − 2, we shift the graph of y = f(x) right 2 units (for the “−2” insidethe<br />

parentheses), and then shift the resulting graph 2 units downward.<br />

(e)Toobtainthegraphofy = −f(x),wereflect the graph of y = f(x) about the x-axis.<br />

(f)Toobtainthegraphofy = f −1 (x),wereflect the graph of y = f(x) about the line y = x (assuming f is one–to-one).<br />

11. y = − sin 2x: Start with the graph of y =sinx, compress horizontally by a factor of 2,andreflect about the x-axis.<br />

13. y = 1 (1 + 2 ex ):<br />

Startwiththegraphofy = e x ,<br />

shift 1 unit upward, and compress<br />

vertically by a factor of 2.<br />

15. f(x) = 1<br />

x +2 :<br />

Startwiththegraphoff(x) =1/x<br />

and shift 2 units to the left.

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