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Solução_Calculo_Stewart_6e

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F.<br />

TX.10<br />

24 ¤ CHAPTER 1 FUNCTIONS AND MODELS<br />

13. The first term, 10 sin x, has period 2π and range [−10, 10]. It will be the dominant term in any “large” graph of<br />

y =10sinx +sin100x, as shown in the first figure. The second term, sin 100x,hasperiod 2π = π and range [−1, 1].<br />

100 50<br />

Itcausesthebumpsinthefirst figure and will be the dominant term in any “small” graph, as shown in the view near the<br />

origin in the second figure.<br />

15. We must solve the given equation for y to obtain equations for the upper and<br />

lower halves of the ellipse.<br />

4x 2 +2y 2 =1 ⇔ 2y 2 =1− 4x 2 ⇔ y 2 = 1 − 4x2<br />

2<br />

<br />

1 − 4x<br />

2<br />

y = ±<br />

2<br />

⇔<br />

17. From the graph of y =3x 2 − 6x +1<br />

and y =0.23x − 2.25 in the viewing<br />

rectangle [−1, 3] by [−2.5, 1.5],itis<br />

difficult to see if the graphs intersect.<br />

If we zoom in on the fourth quadrant,<br />

we see the graphs do not intersect.<br />

19. From the graph of f(x) =x 3 − 9x 2 − 4, we see that there is one solution<br />

of the equation f(x) =0and it is slightly larger than 9. By zooming in or<br />

using a root or zero feature, we obtain x ≈ 9.05.<br />

21. We see that the graphs of f(x) =x 2 and g(x) =sinx intersect twice. One<br />

solution is x =0. The other solution of f = g is the x-coordinate of the<br />

point of intersection in the first quadrant. Using an intersect feature or<br />

zooming in, we find this value to be approximately 0.88. Alternatively, we<br />

could find that value by finding the positive zero of h(x) =x 2 − sin x.<br />

Note: After producing the graph on a TI-83 Plus, we can find the approximate value 0.88 by using the following keystrokes:<br />

. The “1” is just a guess for 0.88.

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