The Computable Differential Equation Lecture ... - Bruce E. Shapiro
The Computable Differential Equation Lecture ... - Bruce E. Shapiro
The Computable Differential Equation Lecture ... - Bruce E. Shapiro
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CHAPTER 4. IMPROVING ON EULER’S METHOD 83<br />
✬<br />
Algorithm 4.1. Backward Euler Method Using Fixed Point<br />
Iteration. To solve the initial value problem<br />
y ′ = f(t, y), y(t 0 ) = y 0<br />
on an interval [t 0 , t max ] with a fixed step size h.<br />
1. input: f(t, y), t 0 , y 0 , h, t max , tol<br />
2. output: (t 0 , y 0 )<br />
3. let t = t 0 , y = y 0<br />
4. while t < t max<br />
(a) let i = 0<br />
(b) let y (0)<br />
next = y + hf(t + h, y) ⇐=<br />
(c) Repeat:<br />
y (i+1)<br />
next<br />
i = i + 1<br />
= y + hf(t + h, y (i)<br />
next ) ⇐=<br />
✩<br />
✫<br />
until |y (i+1)<br />
next<br />
(d) let y = y (i+1)<br />
next<br />
(e) let t = t + h<br />
(f) let t n = t, y n = y<br />
− y (i)<br />
next | < tol<br />
(g) output: (t 0 , y 0 ), . . . , (t n , y n )<br />
✪<br />
<strong>The</strong>orem 4.6 (Newton’s Method). To find the root r of the scalar equation<br />
g(t) = 0, iterate on<br />
r (i+1) = r (i) − g(r(i) )<br />
g ′ (r (i) )<br />
To find the root r of the vector equation g(y) = 0, iterate on<br />
(4.106)<br />
( ) ∣<br />
∂g(y)<br />
−1∣∣∣∣y=r r (i+1) = r (i) −<br />
g(r (i) ) ⇐= (4.107)<br />
∂y<br />
(i)<br />
For the scalar IVP, we can use Newton’s method to find the root of<br />
g(y n ) = y n − y n−1 − hf(t, y n ) = 0 (4.108)<br />
c○2007, B.E.<strong>Shapiro</strong><br />
Last revised: May 23, 2007<br />
Math 582B, Spring 2007<br />
California State University Northridge