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The Computable Differential Equation Lecture ... - Bruce E. Shapiro

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CHAPTER 3. APPROXIMATE SOLUTIONS 51<br />

3.3 <strong>The</strong> Fundamental Inequality<br />

We can prove that the Epsilon-approximate solution converges to an exact solution<br />

of the differential equation, giving us a proof of the fundamental existence theorem.<br />

This proof will be presented in the following section. Here we will present a basic<br />

inequality that is often used in the theory of differential equations.<br />

Lemma 3.1. Suppose that ∂f/∂y is bounded for all (t, y) ∈ D. <strong>The</strong>n f(t, y) is<br />

Lipshitz on D with Lipshitz Constant<br />

K = sup<br />

∂f<br />

∣ ∂y ∣ (3.66)<br />

Proof. By the Mean Value theorem there exists some number c between between y 1<br />

and y 2 such that<br />

∂f(t, c)<br />

f(t, y 2 ) − f(t, y 1 ) = (y 2 − y 1 ) (3.67)<br />

∂y<br />

Since ∣ ∣∣∣ ∂f(t, c)<br />

∂y ∣ ≤ K (3.68)<br />

we have<br />

and thus the function is Lipshitz in y.<br />

|f(t, y 2 ) − f(t, y 1 )| ≤ K|y 2 − y 1 | (3.69)<br />

Lemma 3.2. Suppose D is not convex, but can be embedded in a convex domain<br />

D ′ . Let δ > 0 be the shortest distance between the boundaries of D and D ′ . Suppose<br />

that f is continuous and bounded by M in D, and that ∂f/∂y exists and is bounded<br />

by N in D ′ then f(t, y) is Lipshitz in y in D with Lipshitz Constant<br />

(<br />

K = max N, 2M )<br />

(3.70)<br />

δ<br />

Proof. Let P = (t, y 1 ), Q = (t, y 2 ) ∈ D.<br />

<strong>The</strong>n if |y 1 − y 2 | > δ,<br />

∣ f(t, y 1 ) − f(t, y 2 ) ∣∣∣<br />

∣<br />

≤ |f(t, y 1)| + |f(t, y 2 )|<br />

= 2M y 1 − y 2 min |y 1 − y 2 | δ<br />

thus<br />

(3.71)<br />

|f(t, y 1 ) − f(t, y 2 )| ≤ 2M δ |f(t, y 1) − f(t, y 2 )| (3.72)<br />

(<br />

≤ max N, 2M )<br />

|f(t, y 1 ) − f(t, y 2 )| (3.73)<br />

δ<br />

≤ K|f(t, y 1 ) − f(t, y 2 )| (3.74)<br />

Alternatively, if |y 1 −y 2 | ≤ δ, the line segment PQ still lies entirely in D ′ . But since<br />

D ′ is convex, we can apply lemma 3.1 to conclude that N is a Lipshitz constant.<br />

Hence the Lemma is proved.<br />

c○2007, B.E.<strong>Shapiro</strong><br />

Last revised: May 23, 2007<br />

Math 582B, Spring 2007<br />

California State University Northridge

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