Trigonometric Integrals - Bruce E. Shapiro
Trigonometric Integrals - Bruce E. Shapiro
Trigonometric Integrals - Bruce E. Shapiro
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Math 150A TOPIC 7. TRIGONOMETRIC INTEGRALS<br />
Hence<br />
∫<br />
sec 3 x dx = 1 (sec x tan x + ln | sec x + tan x|) + C<br />
2 (7.24j)<br />
Now we collect some rules for products of secants and tangents.<br />
∫<br />
tan m x sec n x dx<br />
1. If the exponent on the tangent is even<br />
(a) Save one factor of sec 2 x to use as d tan x.<br />
(b) Substitute sec 2 x = 1 + tan 2 x in the remaining secants.<br />
(c) Use a substitution u = tan x and integrate.<br />
2. Otherwise, if the exponent of the secant is odd and the exponent of<br />
the tangent is at least 1,<br />
(a) Save one factor sec x tan x to use as d sec x.<br />
(b) Substitute tan 2 x = sec 2 x − 1 for all the remaining tangents.<br />
(c) Use a substitution u = sec x and integrate.<br />
3. Otherwise, look for some other way to simplify the integral.<br />
Finally, we also consider simple products of multiple-angle formulas, which<br />
we demonstrate by example.<br />
Example 7.11<br />
∫ π/4<br />
0<br />
cos(2x) sin(12x) dx We use the trigonometric identity<br />
sin θ cos ψ = 1 [sin(θ − ψ) + sin(θ + ψ)]<br />
2 (7.25a)<br />
to obtain<br />
∫ π/4<br />
0<br />
∫ π/4<br />
cos(2x) sin(12x) dx = 1 [sin(10x) + sin(14x)] dx (7.25b)<br />
2 0<br />
= 1 [ ]∣ −1<br />
−1 ∣∣∣<br />
π/4<br />
cos(10x) +<br />
2 10 14 cos(14x) (7.25c)<br />
0<br />
= 1 [ −1<br />
2 10 cos 5π 2 − 1<br />
14 cos 7π 2 + 1<br />
10 + 1 ]<br />
14<br />
(7.25d)<br />
= 3 35<br />
(7.25e)<br />
Page 28 « 2012. Last revised: February 26, 2013