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Trigonometric Integrals - Bruce E. Shapiro

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Math 150A TOPIC 7. TRIGONOMETRIC INTEGRALS<br />

Hence<br />

∫<br />

sec 3 x dx = 1 (sec x tan x + ln | sec x + tan x|) + C<br />

2 (7.24j)<br />

Now we collect some rules for products of secants and tangents.<br />

∫<br />

tan m x sec n x dx<br />

1. If the exponent on the tangent is even<br />

(a) Save one factor of sec 2 x to use as d tan x.<br />

(b) Substitute sec 2 x = 1 + tan 2 x in the remaining secants.<br />

(c) Use a substitution u = tan x and integrate.<br />

2. Otherwise, if the exponent of the secant is odd and the exponent of<br />

the tangent is at least 1,<br />

(a) Save one factor sec x tan x to use as d sec x.<br />

(b) Substitute tan 2 x = sec 2 x − 1 for all the remaining tangents.<br />

(c) Use a substitution u = sec x and integrate.<br />

3. Otherwise, look for some other way to simplify the integral.<br />

Finally, we also consider simple products of multiple-angle formulas, which<br />

we demonstrate by example.<br />

Example 7.11<br />

∫ π/4<br />

0<br />

cos(2x) sin(12x) dx We use the trigonometric identity<br />

sin θ cos ψ = 1 [sin(θ − ψ) + sin(θ + ψ)]<br />

2 (7.25a)<br />

to obtain<br />

∫ π/4<br />

0<br />

∫ π/4<br />

cos(2x) sin(12x) dx = 1 [sin(10x) + sin(14x)] dx (7.25b)<br />

2 0<br />

= 1 [ ]∣ −1<br />

−1 ∣∣∣<br />

π/4<br />

cos(10x) +<br />

2 10 14 cos(14x) (7.25c)<br />

0<br />

= 1 [ −1<br />

2 10 cos 5π 2 − 1<br />

14 cos 7π 2 + 1<br />

10 + 1 ]<br />

14<br />

(7.25d)<br />

= 3 35<br />

(7.25e)<br />

Page 28 « 2012. Last revised: February 26, 2013

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