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Trigonometric Integrals - Bruce E. Shapiro

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Math 150A TOPIC 7. TRIGONOMETRIC INTEGRALS<br />

If we divide equation (7.4) by cos x we get a similar equation relating the<br />

tangent and secant of an angle:<br />

Finally, we add the double angle formula for a sine<br />

tan 2 x + 1 = sec 2 x (7.8)<br />

sin 2x = 2 sin x cos x (7.9)<br />

and the following product-angle formulas to the mix:<br />

sin x cos y = 1 [sin(x − y) + sin(x + y)] (7.10)<br />

2<br />

sin x sin y = 1 [cos(x − y) − cos(x + y)] (7.11)<br />

2<br />

cos x cos y = 1 [cos(x − y) + cos(x + y)] (7.12)<br />

2<br />

Equations (7.4) through (7.12) will be our main tools for finding substitutions<br />

that reduce integrals to manageable proportions.<br />

∫<br />

Example 7.1 sin 2 x dx This is perhaps the most basic of the integrals<br />

of this form. We can use the identity (7.7) to obtain<br />

∫<br />

sin 2 x dx = 1 ∫<br />

(1 − cos 2x) dx (7.13a)<br />

2<br />

= 1 2 x − 1 sin 2x + C (7.13b)<br />

4<br />

When there is a single odd power (e.g., cos 3 x, sin 3 x, cos 5 x, sin 5 x, . . . ), we<br />

“reserve” one factor for the derivative, and replace all the other factors with<br />

the identity (7.4), followed by a u-substitution of u = cos x or u = sin x.<br />

∫<br />

Example 7.2 cos 3 x dx<br />

∫<br />

∫<br />

cos 3 x dx = cos x · cos 2 x dx<br />

(7.14a)<br />

∫<br />

= cos x (1 − sin 2 x) dx<br />

(7.14b)<br />

∫<br />

= (1 − u 2 ) du where u = sin x (7.14c)<br />

= u − 1 3 u3 + C (7.14d)<br />

= sin x − 1 3 sin3 x + C (7.14e)<br />

Page 22 « 2012. Last revised: February 26, 2013

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