Multivariate Calculus - Bruce E. Shapiro
Multivariate Calculus - Bruce E. Shapiro
Multivariate Calculus - Bruce E. Shapiro
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LECTURE 8. FUNCTIONS OF TWO VARIABLES 53<br />
Figure 8.1: Visualization of a multivariate function. In both figures, the domain<br />
represents a set in the xy-plane, and the range is a subset of the z-axis. In the<br />
top, the function is visualized as a mapping between sets. The arrows indicate the<br />
mapping for four points in the domain that are mapped to three points in the range.<br />
The bottom figure visualizes this as a mapping embedded in 3D space, with each<br />
point z = f(x, y) represented as a 3-tuple (x, y, z) in space.<br />
(a) Don’t divide by zero<br />
(b) Don’t take the square root of a negative number.<br />
Anything that remains is part of the natural domain of the function<br />
“Exclude the impossible and what remains, however improbable, is the<br />
solution.” [Sherlock Holmes]<br />
Example 8.4 Find the natural domain of the function<br />
f(x, y) = √ 16 − x 2 − y 2<br />
Solution. Since we can’t take the square root of a negative number, we exclude<br />
points where<br />
16 − x 2 − y 2 < 0<br />
Thus the natural domain is the set of all (x, y) where<br />
16 − x 2 − y 2 ≥ 0,<br />
Math 250, Fall 2006 Revised December 6, 2006.