Multivariate Calculus - Bruce E. Shapiro
Multivariate Calculus - Bruce E. Shapiro
Multivariate Calculus - Bruce E. Shapiro
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LECTURE 5. VELOCITY, ACCELERATION, AND CURVATURE 43<br />
Definition 5.4 The Principal unit normal vector N is<br />
N =<br />
dT/ ds<br />
∥<br />
∥dT / ds ∥ = 1 dT<br />
κ ds<br />
(5.17)<br />
N is not the only unit normal vector to the curve at P; in fact, on could define<br />
an infinite number of unit normal vectors to a curve at any given point. To do so,<br />
merely find the plane perpendicular to the tangent vector. An vector in this plane<br />
is normal to the curve. One such vector that is often used is the following, which is<br />
perpendicular to both T and N.<br />
Definition 5.5 The binormal vector is B = T × N .<br />
Definition 5.6 The triple of normal vectors {T, N, B} is called the trihedral at<br />
P.<br />
Definition 5.7 The plane formed by T and N is called the osculating plane at<br />
P.<br />
Since T = v / ‖v‖ we can write<br />
v = T ‖v‖ = T ds<br />
dt<br />
(see equation (5.10).) The acceleration vector (equation (5.11)) is<br />
a = dv<br />
dt = d (<br />
T ds )<br />
= T d2 s<br />
dt dt dt + dT ds<br />
dt dt<br />
( )<br />
= T d2 s dT<br />
dt + ds ds<br />
ds dt dt<br />
= T d2 s<br />
dt + dT ( ) ds 2<br />
ds dt<br />
From equation (5.17),<br />
(5.18)<br />
( )<br />
a = T d2 s ds 2<br />
dt + κN (5.19)<br />
dt<br />
Equation (5.19) breaks the acceleration into two perpendicular components, one<br />
that is tangent to the curve:<br />
a ‖ = d2 s<br />
dt<br />
and one that is perpendicular to the curve:<br />
a ⊥ = κ<br />
( ) ds 2<br />
dt<br />
so that<br />
a = a ‖ T + a ⊥ N<br />
Math 250, Fall 2006 Revised December 6, 2006.