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Multivariate Calculus - Bruce E. Shapiro

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LECTURE 5. VELOCITY, ACCELERATION, AND CURVATURE 43<br />

Definition 5.4 The Principal unit normal vector N is<br />

N =<br />

dT/ ds<br />

∥<br />

∥dT / ds ∥ = 1 dT<br />

κ ds<br />

(5.17)<br />

N is not the only unit normal vector to the curve at P; in fact, on could define<br />

an infinite number of unit normal vectors to a curve at any given point. To do so,<br />

merely find the plane perpendicular to the tangent vector. An vector in this plane<br />

is normal to the curve. One such vector that is often used is the following, which is<br />

perpendicular to both T and N.<br />

Definition 5.5 The binormal vector is B = T × N .<br />

Definition 5.6 The triple of normal vectors {T, N, B} is called the trihedral at<br />

P.<br />

Definition 5.7 The plane formed by T and N is called the osculating plane at<br />

P.<br />

Since T = v / ‖v‖ we can write<br />

v = T ‖v‖ = T ds<br />

dt<br />

(see equation (5.10).) The acceleration vector (equation (5.11)) is<br />

a = dv<br />

dt = d (<br />

T ds )<br />

= T d2 s<br />

dt dt dt + dT ds<br />

dt dt<br />

( )<br />

= T d2 s dT<br />

dt + ds ds<br />

ds dt dt<br />

= T d2 s<br />

dt + dT ( ) ds 2<br />

ds dt<br />

From equation (5.17),<br />

(5.18)<br />

( )<br />

a = T d2 s ds 2<br />

dt + κN (5.19)<br />

dt<br />

Equation (5.19) breaks the acceleration into two perpendicular components, one<br />

that is tangent to the curve:<br />

a ‖ = d2 s<br />

dt<br />

and one that is perpendicular to the curve:<br />

a ⊥ = κ<br />

( ) ds 2<br />

dt<br />

so that<br />

a = a ‖ T + a ⊥ N<br />

Math 250, Fall 2006 Revised December 6, 2006.

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