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Multivariate Calculus - Bruce E. Shapiro

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184 LECTURE 22. LINE INTEGRALS<br />

Recall from integral calculus the following statement of the fundamental theorem<br />

of calculus: If f is differentiable and f ′ (t) is integrable on some interval (a, b) then<br />

∫ b<br />

a<br />

f ′ (t)dt = f(b) − f(a) (22.20)<br />

In the generalization to line integrals, the derivative becomes a directional derivative,<br />

but otherwise the statement of the theorem remains almost unchanged.<br />

Theorem 22.1 Fundamental Theorem of <strong>Calculus</strong> for Line Integrals Suppose<br />

that C is a piecewise smooth curve that can be parameterized as<br />

for some open set S ⊂ R 3 , and let<br />

C = {r(t), a ≤ t ≤ b} ⊂ S (22.21)<br />

A = r(a) (22.22)<br />

B = r(b) (22.23)<br />

Then if f : S ↦→ R 3 is continuously differentiable on S,<br />

∫<br />

∇f(r) · dr = f(B) − f(A) (22.24)<br />

C<br />

Since the directional derivative in the direction of v(t) is<br />

D v f(r) = ∇f(r(t)) · v(t)<br />

= ∇f(r(t)) · dr(t)<br />

dt<br />

then the left-hand side of equation 22.24 can be rewritten to give<br />

∫<br />

∫ b<br />

∇f(r) · r = D v f(r(t))dt (22.25)<br />

C<br />

and the fundamental theorem of calculus for line integrals becomes<br />

∫ b<br />

Proof. Expanding the directional derivative,<br />

a<br />

a<br />

D v f(r(t))dt = f(B) − f(A) (22.26)<br />

D v f(r(t)) = ∇f(r(t)) · v<br />

( ∂f(r(t))<br />

= , ∂f(r(t)) , ∂f(r(t))<br />

∂x ∂y ∂z<br />

= ∂f(r(t)) dx<br />

∂x dt + ∂f(r(t)) dy<br />

∂y dt + ∂f(r(t))<br />

∂z<br />

= df(r(t))<br />

dt<br />

) ( dx<br />

·<br />

dt , dy<br />

dt , dz<br />

dt<br />

Revised December 6, 2006. Math 250, Fall 2006<br />

dz<br />

dt<br />

)

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