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Multivariate Calculus - Bruce E. Shapiro

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LECTURE 22. LINE INTEGRALS 183<br />

so that the second integral becomes<br />

∫<br />

C 2<br />

F · dr =<br />

=<br />

=<br />

=<br />

∫ 1<br />

0<br />

∫ 1<br />

0<br />

∫ 1<br />

0<br />

(x, 2y) · d<br />

dt<br />

(1 − t, 2t)dt<br />

(1 − t, 4t) · (−1, 2)dt<br />

(−1 + 9t)dt<br />

(−t + 9t2<br />

2<br />

)∣ ∣∣∣<br />

1<br />

0<br />

= 7 2<br />

Therefore the integral over C is<br />

∮ ∫ ∫<br />

F · dr = F · dr + F · dr = − 7<br />

C<br />

C 1 C 2<br />

2 + 7 2 = 0 <br />

Example 22.4 A particle travels along the helix<br />

in the vector field<br />

r = (cos t, sin t, 2t)<br />

F = (x, z, −xy)<br />

Find the total work done over the time period 0 ≤ t ≤ 3π.<br />

Solution. The work is given by<br />

W =<br />

=<br />

=<br />

=<br />

∫ 3π<br />

0<br />

∫ 3π<br />

0<br />

∫ 3π<br />

0<br />

∫ 3π<br />

0<br />

= −3<br />

F · r ′ dt<br />

(x, z, −xy) · d (cos t, sin t, 2t)dt<br />

dt<br />

(cos t, 2t, − cos t sin t) · (− sin t, cos t, 2)dt<br />

(− cos t sin t + 2t cos t − 2 cos t sin t) dt<br />

∫ 3π<br />

0<br />

∫ 3π<br />

cos t sin tdt + 2 t cos tdt<br />

0<br />

Using the integral formulas ∫ sin t cos tdt = 1 2 sin2 t and ∫ t cos t = cos t + t sin t gives<br />

( )∣ 1 ∣∣∣<br />

3π<br />

W = −3<br />

2 sin2 t + 2 (cos t + t sin t)| 3π<br />

0<br />

0<br />

= 2(cos 3π − cos 0) = −4 <br />

Math 250, Fall 2006 Revised December 6, 2006.

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