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Multivariate Calculus - Bruce E. Shapiro

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LECTURE 17. DOUBLE INTEGRALS OVER GENERAL REGIONS 143<br />

Figure 17.8: The solid formed by the paraboloid z = 9 − x 2 − y 2 and the xy plane.<br />

xy plane. This occurs when z = 0. So that means the domain is<br />

0 = 9 − x 2 − y 2 ⇒ y 2 + x 2 = 3 2<br />

which is a circle of radius 3 centered at the origin. Since we only want the part of<br />

the circle that is in the first quadrant, we need x and y both positive. To cover the<br />

upper right hand corner of a circle of radius 3 centered at the origin, we can let x<br />

increase from 0 to 3 and y increase from 0 to y = √ 9 − x 2 Therefore the volume is<br />

V =<br />

=<br />

=<br />

=<br />

= 2 3<br />

∫ 3 ∫ √ 9−x 2<br />

0<br />

∫ 3<br />

0<br />

∫ 3<br />

0<br />

∫ 3<br />

0<br />

(9 − x 2 )<br />

(9 − x 2 − y 2 )dydx<br />

∫ √ 9−x 2<br />

0<br />

(<br />

(9 − x 2 ) y|<br />

0<br />

∫ 3<br />

√<br />

9−x 2<br />

0<br />

(9 − x 2 ) 3/2 dx − 1 3<br />

0<br />

(9 − x 2 ) 3/2 dx<br />

dydx −<br />

)<br />

dx − 1 3<br />

∫ 3<br />

0<br />

∫ 3 ∫ √ 9−x 2<br />

0 0<br />

∫ 3<br />

0<br />

(9 − x 2 ) 3/2 dx<br />

√<br />

9−x 2<br />

y 2 dydx<br />

y 3 | 0 dx<br />

Math 250, Fall 2006 Revised December 6, 2006.

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