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Multivariate Calculus - Bruce E. Shapiro

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140 LECTURE 17. DOUBLE INTEGRALS OVER GENERAL REGIONS<br />

Example 17.5 Find the iterated integral<br />

∫ 12 ∫ x+3<br />

−2 −x 2<br />

(x + 3y)dxdy<br />

Solution. Separating the integral into two parts and factoring what we can gives<br />

∫ 12 ∫ x+3<br />

−2<br />

(x + 3y)dydx =<br />

=<br />

=<br />

=<br />

=<br />

∫ 12 ∫ x+3<br />

−2<br />

∫ 12<br />

−2<br />

∫ 12<br />

−2<br />

∫ 12<br />

−2<br />

∫ 12<br />

−2<br />

x<br />

−x 2 xdydx +<br />

∫ x+3<br />

−x 2 dydx + 3<br />

x(y| x+3<br />

−x 2 )dx + 3<br />

∫ 12 ∫ x+3<br />

−2 −x<br />

∫ 2<br />

12 ∫ x+3<br />

−2<br />

∫ 12<br />

−2<br />

x(x + 3 + x 2 )dx + 3 2<br />

(x 2 + 3x + x 3 )dx + 3 2<br />

−x 2<br />

3ydydx<br />

ydydx<br />

( 1 2 y2 | x+3 )dx<br />

−x 2<br />

∫ 12<br />

−2<br />

∫ 12<br />

−2<br />

[(x + 3) 2 − (−x 2 ) 2 ]dx<br />

(x + 3) 2 dx − 3 2<br />

∫ 12<br />

−2<br />

x 4 dx<br />

Integrating and plugging in numbers, we find that<br />

∫ 12 ∫ x+3<br />

−2<br />

−x 2 (x + 3y)dydx = ( 1 3 x3 + 3 2 x2 + 1 4 x4 )| 12<br />

−2 + 3 1<br />

2 3 (x + 3)3 | 12<br />

−2 − 3 2<br />

1<br />

5 x5 | 12<br />

= 1 3 (12)3 + 3 2 (12)2 + 1 4 (12)4 − 1 3 (−8) − 3 2 (4) − 1 2 (16)<br />

+ 1 2 (153 − (−8)) − 3 10 (125 − (−32))<br />

= 576 + 216 + 5184 + 8 − 6 − 8 + 1691.5 − 124432<br />

3<br />

≈<br />

−116775.83 <br />

−2<br />

Figure 17.7: The plane z = 6 − 2x − 3y and its cross-section on the xy plane.<br />

Example 17.6 Find the volume of the tetrahedron bounded by the coordinate planes<br />

and the plane z = 6 − 2x − 3y.<br />

Revised December 6, 2006. Math 250, Fall 2006

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