Multivariate Calculus - Bruce E. Shapiro
Multivariate Calculus - Bruce E. Shapiro Multivariate Calculus - Bruce E. Shapiro
134 LECTURE 16. DOUBLE INTEGRALS OVER RECTANGLES then du = 2dx, because y is a constant. When x=1, u=1+y; When x=3, u=9+y. Therefore, ∫ 3 x (x 2 + y) 2 dx = 1 ∫ 9+y du 2 u 2 2 1 1 2 = 1 2 1+y ∫ 9+y 1+y u −2 du = 1 2 (−u−1 ) ∣ 9+y 1+y = 1 [ −1 2 9 + y + 1 ] 1 + y Substituting this back into the original iterated integral, we find that ∫ 5 ∫ 3 ∫ x 5 [ (x 2 + y) 2 dxdy = 1 −1 2 9 + y + 1 ] dy 1 + y = 1 2 [− ln(9 + y) + ln(1 + y)]|5 2 = 1 [(− ln 14 + ln 6) − (− ln 11 + ln 3)] 2 = 1 (6)(11) ln 2 (14)(3) = 1 11 ln 2 7 = ln √ 11/7 ≈ 0.226 When we integrate over non-rectangular regions, the limits on the inner integral will be functions that depend on the variable in the outer integral. Example 16.9 Find the area of the triangle R = {(x, y) : 0 ≤ x ≤ b, 0 ≤ y ≤ mx} using double integrals and show that it gives the usual formula y = (base)(height)/2 Solution. ∫ b A = R dxdy = 0 ∫ mx 0 dydx = ∫ b 0 mxdx = mb 2 /2 We can find the height of the triangle by oberserving that at x = b, y = mb, therefore the height is h = mb, and hence A = mb 2 /2 = (mb)(b)/2 = (height)(base)/2 We will consider integrals over non-rectangular regions in greater detail in the following section. Revised December 6, 2006. Math 250, Fall 2006
Lecture 17 Double Integrals over General Regions Definition 17.1 Let f(x, y) : D ⊂ R 2 ↦→ R. Then we say that that f is integrable on D if for some rectangle R, which is oriented parallel to the xy axes, the function { f(x, y) if (x, y) ∈ D F (x, y) = 0 otherwise is integrable, and we definitionine the double integral over the set D by f(x, y)dA = F (x, y)dA D R Figure 17.1: The integral over a non-rectangular region is definitionined by extending the domain to an enclosing rectangle. In other words, we extend the domain of f(x, y) from D to some rectangle including D, by definitionining a new function F (x, y) that is zero everywhere outside D, and equal to f on D, and then use our previous definitioninition of the integral over a rectangle. The double integral has the following properties. Theorem 17.1 Linearity. Suppose that f(x, y) and g(x, y) are integrable over D. The for any constants α, β ∈ R (αf(x, y) + βg(x, y)) dA = α f(x, y)dA + β g(x, y)dA D 135 D D
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Lecture 17<br />
Double Integrals over General<br />
Regions<br />
Definition 17.1 Let f(x, y) : D ⊂ R 2 ↦→ R. Then we say that that f is integrable<br />
on D if for some rectangle R, which is oriented parallel to the xy axes, the function<br />
{<br />
f(x, y) if (x, y) ∈ D<br />
F (x, y) =<br />
0 otherwise<br />
is integrable, and we definitionine the double integral over the set D by<br />
<br />
<br />
f(x, y)dA = F (x, y)dA<br />
D<br />
R<br />
Figure 17.1: The integral over a non-rectangular region is definitionined by extending<br />
the domain to an enclosing rectangle.<br />
In other words, we extend the domain of f(x, y) from D to some rectangle including<br />
D, by definitionining a new function F (x, y) that is zero everywhere outside D, and<br />
equal to f on D, and then use our previous definitioninition of the integral over a<br />
rectangle. The double integral has the following properties.<br />
Theorem 17.1 Linearity. Suppose that f(x, y) and g(x, y) are integrable over D.<br />
The for any constants α, β ∈ R<br />
<br />
<br />
<br />
(αf(x, y) + βg(x, y)) dA = α f(x, y)dA + β g(x, y)dA<br />
D<br />
135<br />
D<br />
D