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Multivariate Calculus - Bruce E. Shapiro

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LECTURE 14. UNCONSTRAINED OPTIMIZATION 105<br />

The Second Derivative Test: Classifying the Stationary<br />

Points<br />

Theorem 14.2 Second Derivative Test.Suppose that f(x, y) has continuous partial<br />

derivatives in some neighborhood of (a, b) where<br />

Define the function<br />

and the number<br />

Then<br />

f x (a, b) = f y (a, b) = 0<br />

D(x, y) = f xx f yy − f 2 xy<br />

d = D(a, b) = f xx (a, b)f yy (a, b) − (f xy (a, b)) 2<br />

1. If d > 0 and f xx (a, b) < 0, then f(a, b) is a local maximum;<br />

2. If d > 0 and f xx (a, b) > 0, then f(a, b) is a local minimum;<br />

3. If d < 0 then f(a, b) is a saddle point;<br />

4. If d = 0 the second-derivative test is inconclusive.<br />

Proof of the Second Derivative Test. Given at the end of this section.<br />

<br />

Example 14.3 Classify the stationary points of f(x, y) = x 3 + y 3 − 6xy<br />

Solution. We found in the previous example that stationary points occur at (0, 0)<br />

and (2, 2), and that<br />

f x = 3x 2 − 6y<br />

Hence the second derivatives are<br />

Thus<br />

At (a, b) = (0, 0),<br />

f y = 3y 2 − 6x<br />

f xx = 6x<br />

f xy = −6<br />

f yy = 6y<br />

D(x, y) = f xx f yy − f 2 xy = (6x)(6y) − (−6) 2 = 36xy − 36<br />

hence (0, 0) is a saddle point.<br />

and<br />

At (a, b) = (2, 2),<br />

Hence (2, 2) is a local minimum.<br />

d = −36 < 0<br />

d = (36)(2)(2) − 36 > 0<br />

f xx 2, 2 = 12 > 0<br />

<br />

Math 250, Fall 2006 Revised December 6, 2006.

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