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Multivariate Calculus - Bruce E. Shapiro

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102 LECTURE 14. UNCONSTRAINED OPTIMIZATION<br />

1. All points on the boundary of J;<br />

2. All stationary points, namely, any point where ∇f(x, y) = 0;<br />

3. All singular points, namely, any points where f(x, y) or ∇f(x, y) are undefined.<br />

The candidate extrema are sometimes called critical points; some authors restrict<br />

the use of this term to describe the stationary points.<br />

Stationary points occur when ∇f(x, y) = 0; this requires all of the derivatives<br />

to be zero:<br />

∂f<br />

∂x = 0 = ∂f<br />

∂y<br />

Recall from one-variable calculus that three different things could happen at a stationary<br />

point where f ′ (a) = 0:<br />

• f(x) could have a local maximum at x = a, as, for example, occurs for f(x) =<br />

−(x − a) 2<br />

• f(x) could have a local minimum at x = a, as, for example, occurs for f(x) =<br />

(x − a) 2<br />

• f(x) could have an inflection point at x = a, as, for example, occurs for<br />

f(x) = (x − a) 3<br />

For multivariate functions there are three types of stationary points: local maxima,<br />

local minima, and saddle points. Saddle points are the generalization of inflection<br />

points. At a saddle point, in some vertical cross-sections, the function appears to<br />

have a local minimum, while in other vertical cross-sections, the function appears<br />

to have a local maximum.<br />

Example 14.1 Find the stationary points of the function f(x, y) = x 2 − 7xy +<br />

12y 2 − y<br />

Solution. The function has stationary points when f x (x, y) = f y (x, y) = 0. Differentiating,<br />

∂f<br />

∂x = 0 ⇒ ∂<br />

∂x (x2 − 7xy + 12y 2 − y) = 2x − 7y = 0<br />

⇒ y = 2x/7<br />

∂f<br />

∂y = 0 ⇒ ∂ ∂y (x2 − 7xy + 12y 2 − y) = −7x + 24y − 1 = 0<br />

⇒ 24y = 7x + 1<br />

Combining the two results,<br />

48<br />

49x + 7<br />

x = 7x + 1 = ⇒ x = −7<br />

7 7<br />

Revised December 6, 2006. Math 250, Fall 2006

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