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Lecture Notes in Differential Equations - Bruce E. Shapiro

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46 LESSON 6. EXPONENTIAL RELAXATION<br />

Figure 6.1: Illustration of compound <strong>in</strong>terest at different rates of withdrawal<br />

<strong>in</strong> example 6.1. See text for details.<br />

1200<br />

1000<br />

800<br />

600<br />

400<br />

200<br />

5 10 15 20<br />

If <strong>in</strong>stead W/r > y 0 , the <strong>in</strong>itial rate of change is negative so the amount will<br />

always be less than y 0 and your net deposit is decreas<strong>in</strong>g. The term on the<br />

right is exponentially <strong>in</strong>creas<strong>in</strong>g, but we can only make withdrawals <strong>in</strong>to<br />

the balance is zero. This occurs when the right hand side of the equation<br />

is zero.<br />

( )<br />

W W<br />

r = r − y 0 e rt (6.21)<br />

or at a time given by<br />

t = − 1 (<br />

r ln 1 − y )<br />

0r<br />

W<br />

(6.22)<br />

So if you withdraw money at a rate faster than ry 0 you money will rapidly<br />

go away, while if you withdraw at a slower rate, your balance will still<br />

<strong>in</strong>crease. Figure 6.1 shows the net balance assum<strong>in</strong>g a start<strong>in</strong>g deposit of<br />

$1000 and a fixed <strong>in</strong>terest rate of 5% per annum, for rates of withdraw<br />

(bottom to top) of $250, $100, $60, and $40 per year. For the example the<br />

break-even po<strong>in</strong>t occurs when W = ry 0 = (.05)(1000)=$50.<br />

Exponential Relaxation<br />

When τ < 0 we will see that the behavior is quite different - rather then<br />

exponential run-away, the solution is pulled to the value of C, whatever the<br />

<strong>in</strong>itial value. We will call this phenomenon exponential relaxation.<br />

As before, it is convenient to assume that t 0 = 0 and we also def<strong>in</strong>e T =<br />

−τ > 0 as a positive time constant. Then we have<br />

y = C + (y 0 − C)e −t/T (6.23)

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