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Lecture Notes in Differential Equations - Bruce E. Shapiro

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387<br />

Complex Conjugate Pair with nonzero real part.<br />

If 0 < T 2 < 4∆ the eigenvalues will be a complex conjugate pair, with real<br />

part T. T may be either positive or negative, but T = 0 is excluded from<br />

this category (if T = 0, the eigenvalues will either be purely imag<strong>in</strong>ary,<br />

when∆ > 0, or real with opposite signs, if∆ < 0).<br />

Writ<strong>in</strong>g<br />

µ = T/2, ω 2 = 4∆ − T 2 (34.69)<br />

the eigenvalues become λ = µ ± iω, µ, ω ∈ R. Designat<strong>in</strong>g the correspond<strong>in</strong>g<br />

eigenvectors as v and w, the solution is<br />

where<br />

y = e µt [ Ave iωt + Bwe −iωt] (34.70)<br />

= e µt [Av (cos ωt + i s<strong>in</strong> ωt) + Bw (cos ωt − i s<strong>in</strong> ωt)] (34.71)<br />

= e µt [p cos ωt + q s<strong>in</strong> ωt] (34.72)<br />

p = Av + Bw (34.73)<br />

q = i(Av − Bw) (34.74)<br />

are purely real vectors (see exercise 6) for real <strong>in</strong>itial conditions. The factor<br />

<strong>in</strong> parenthesis <strong>in</strong> (34.70) gives closed periodic trajectories <strong>in</strong> the xy plane,<br />

with period 2π/ω; the exponential factor modulates this parameterization<br />

with either a cont<strong>in</strong>ually <strong>in</strong>creas<strong>in</strong>g (µ > 0) or cont<strong>in</strong>ually decreas<strong>in</strong>g (µ <<br />

0) factor.<br />

When µ > 0, the solutions spiral away from the orig<strong>in</strong> as t → ∞ and <strong>in</strong><br />

towards the orig<strong>in</strong> as t → −∞. The orig<strong>in</strong> is called an unstable spiral.<br />

When µ < 0, the solutions spiral away from the orig<strong>in</strong> as t → −∞ and <strong>in</strong><br />

towards the orig<strong>in</strong> as t → ∞; the orig<strong>in</strong> is then called a stable spiral.<br />

Example 34.5. The system<br />

}<br />

x ′ = −x + 2y<br />

y ′ = −2x − 3y<br />

(34.75)<br />

has trace T = −4 and determ<strong>in</strong>ant ∆ = 7; hence the eigenvalues are<br />

λ = 1 2<br />

[<br />

T ± √ ]<br />

T 2 − 4∆ = −2 ± i √ 3 (34.76)

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